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3 years ago

Solve for x in the diagram below.

Mathematics

2 answers:

bija089 [108]3 years ago

8 0

Answer:

x = 12

Step-by-step explanation:

20° + (6x - 2) = 90°

18° + 6x = 90°

6x = 90° - 18°

6x = 72°

x = 72°/6

x = 12

stira [4]3 years ago

8 0

Answer:

Hope it helps buddy! Mark as brainlist please.

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Item 8 factor −5 out of −10a−25.

egoroff_w [7]

To factor a number out of an expression means to divide each term of the expression by that number.

So, if you want to factor $a$ from the expression $x+y+z$ , you'll write it as

$a\left(\dfrac{x}{a}+\dfrac{y}{a}+\dfrac{z}{a}\right)$

So, in your case, when you divide both terms by -5 you get

$-10a \div (-5) = 2a,\quad -25\div (-5) = 5$

So, the expression becomes

$-10a-25 = -5(2a+5)$

5 0

3 years ago

Find the midsegment of triangle ABC so that it is parallel to side BC and label it as segment EG on the graph.

Lelechka [254]

Answer:

Coordinate of E:(-2,3) Coordinate of G: (2.5,1.5)

Parallel: slopes both = -1/3

1/2 segment: EG length= 3 BC length=6: This is the only one I'm not sure about.

I will show the work for both the problems down below.

Step-by-step explanation:

Finding coordinates:

1+(-5)/2=-2 5+1/2=3

(-2,3)

1+4/2= 2.5 5+(-2)/2= 1.5

(2.5,1.5)

Show work verifying the EG and BC are parallel:

You can do this by finding the slope

Slop formula (y2-y1)/(x2-x1)

(1.5-3)/(2.5-(-2))

Then simplify

-1.5/2/5= -1/3 which i your slope. You use the same formula and follow thee same steps for the points of BC and both will come up as -1/4 meaning they are parallel.

Show work verifying that EG and BC are parallel:

Use distance formula to find how long each line is

√(x2-x1)^2+(y2-y1)^2

√(2.5-(-2)^2)+(1.5-3)^2

Simplify

√4.5+(1.5)=3

Do the same thing with BC and you will get 6

7 0

3 years ago

How may minutes is 40% of 2 hours

8090 [49]

Well, we know that 1 hour is 60 minutes which means 2 hours is 120.
so to find the answer we turn 40% into a decimal which would be .40

Take .40 and multiply that by 120.
.40 * 120 is 48

40% of 2 hours is 48 minutes.

Hope this helps!

3 0

3 years ago

Read 2 more answers

Which situation could NOT represent a proportional relationship?

Serhud [2]

Answer:

The weight in x weeks of a puppy that gains 2 pounds per week if it starting weight is 8 pounds.

Step-by-step explanation:

Given:

A proportional relationship is one in which one variable varies directly with the other. Let the dependent variable be y and independent variable be y.

If y is directly proportional to x, then,

$y=kx$ , where, k is a constant of proportionality.

Now, let us check each option and try to express a relationship between them.

Option 1:

The weight in $x$ weeks of a puppy that gains 2 pounds per week if it starting weight is 8 pounds.

Let the weight be represented by $W$ . Initial weight is 8 pounds.

Weight gain per week is 2 pounds. So, weight gain in $x$ weeks is $2x$ .

Therefore, total weight is, $W=8+2x$

This is a linear relationship but not a proportional relationship as it is not of the form $y=kx$ . So, option 1 could NOT represent a proportional relationship.

Option 2:

Cost of purchasing 1 pound of bananas is $ 0.55. So, cost of purchasing $p$ pounds of bananas will be $C=0.55p$ . It is of the form $y=kx$ . So, it represents a proportional relationship.

Option 3:

Number of gallons of water in 1 barrel is 50. So, number of gallons in $x$ barrels will be $N=50x$ . It is of the form $y=kx$ . So, it represents a proportional relationship.

Option 4:

Amount earned by an employee in 1 hour is $ 9.25. So, amount earned in $h$ hours will be $A=9.25h$ . It is of the form $y=kx$ . So, it represents a proportional relationship.