Check the picture below.
so is really just a thick trapezoid, or namely a trapezoidal prism 5 inches thick.
so if we just get the area of the trapezoidal face and multiply by the thickness, we'd get it's volume
![\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{parallel~sides}{bases}\\ h=height\\[-0.5em] \hrulefill\\ a = 8\\ b = 13\\ h = 6 \end{cases}\implies A=\cfrac{6(8+13)}{2}\implies A=63 \\\\\\ \stackrel{\textit{area of the trapezoidal prism}}{63\cdot 5\implies \stackrel{in^3}{315}}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20a%2Cb%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%20%3D%208%5C%5C%20b%20%3D%2013%5C%5C%20h%20%3D%206%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B6%288%2B13%29%7D%7B2%7D%5Cimplies%20A%3D63%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20trapezoidal%20prism%7D%7D%7B63%5Ccdot%205%5Cimplies%20%5Cstackrel%7Bin%5E3%7D%7B315%7D%7D)
Answer:
The vertex is (0, 0).
Step-by-step explanation:
Check out the parent function: y = x^2. The graph is a parabola whose vertex is (0, 0) and which opens upward.
Then y = -x^2 is the same but opens downward. The vertex is (0, 0).
X+x+1+x+2+x+3=50
4x+6=50/-6
4x=50-6=44
x=44:4=11
⇒The 1st number is 11, the 2nd is 12, the 3rd is 13 and the 4th is 14.
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11+12+13+14=50
If you don't understand something,please ask me.
The answer to this is .15%
Answer:
uhm, i'm pretty sure it would be 1,128 because between each term is 13 units, and the first three terms are given. and 89-3 is 86. and 86*13=1,118. since the last term was 10, you need to add 10 to that, making your answer 1,128
