Answer:
The set of numbers that could not represent the three sides of a right triangle are;
{9, 24, 26}
Step-by-step explanation:
According to Pythagoras's theorem, when the lengths of the three sides of a right triangle includes two legs, 'x', and 'y', and the hypotenuse side 'r', we have;
r² = x² + y²
Where;
r > x, r > y
Therefore, analyzing the options using the relationship between the numbers forming the three sides of a right triangle, we have;
Set 1;
95² = 76² + 57², therefore, set 1 represents the three sides of a right triangle
Set 2;
82² = 80² + 18², therefore, set 2 represents the three sides of a right triangle
Set 3;
26² = 24² + 9², therefore, set 3 could not represent the three sides of a right triangle
Set 4;
39² = 36² + 15², therefore, set 4 represents the three sides of a right triangle
Answer:
option B. MB/AM=NC/AN
Step-by-step explanation:
we know that
The <u><em>Triangle Proportionality Theorem</em></u> states that if a line is parallel to one side of a triangle and it intersects the other two sides, then it divides those sides proportionally
In this problem
MN is parallel to BC
MN intersect AC and divide into AN and NC
MN intersect AB and divide into AM and MB
so
Applying the Triangle Proportionality Theorem
Rewrite
First factor each number
39=3*13
52=4*13
Now find the greatest common factor, which in our case is 13.
Answer: 13
the radius: r^2 = 81
r =9
c = 2*pi*r
= 2 * pi * 9
= 18 *pi
Answer: 18*pi or approximately 56.62
