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2 years ago

Explain how to solve one absolute value equation by writing it as two equations.

1 answer:

5 0

If you have
|a|=b, then solve for the variable in euations
a=b and a=-b
for ineqalities, it is much trickier

for
|a|>b, assume a>b and a<-b
for
|a|<b, asssume -b<a<b

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find the value of r so that the line that passes through (5, r) and (2, -3) has a slope of 4/3. a. 1 b. 7 c. (13/9) d. -1

Margaret [11]

Slope = (-3 - r) / (2 - 5)

Slope = <span>(-3 - r) / -3 = 4/3

-(-3 - r) = 4

3 + r = 4

r = 4 - 3

r = 1 option b.</span>

4 0

2 years ago

C bisects AB. If AC = 8x - 1 and BC = 4x + 19, what is the length of AB?

tensa zangetsu [6.8K]

The length of AB is 78 units.

<h3>What is a Line Segment?</h3>

A line segment is defined as a measured path between two places. Line segments can make up any polygon's sides because they have a set length.

The figure is given below shows a line segment AB , where the length of line segment AB refers to the distance between its endpoints, A and B.

Given that C is the midpoint of AB

AC = 8x - 1 and BC = 4x + 19,

A______________C______________B

⇒ AB = AC+ BC

Since C is the bisects of AB, So AC = BC

⇒ AB = AC+ BC

⇒ AB = 2AC

Substitute the values of If AC = 8x - 1 and BC = 4x + 19,

⇒ 8x - 1 = 4x + 19,

Rearranging the terms in the above equation,

⇒ 8x - 4x = 1 + 19,

⇒ 4x = 20,

⇒ x = 20/4,

⇒ x = 5

So AB = 2AC

⇒ AB = 2(8x - 1) = 16x -2

Substitute the value of x = 5 in the above equation,

⇒ AB = 16(5) -2

⇒ AB = 78

Hence, the length of AB is 78 units.

Learn more about the line segment here:

brainly.com/question/25727583

#SPJ1

8 0

1 year ago

Solve 3x^2 + 6x+15=0

Elden [556K]

Answer:

The solution of given equation is ( - 1 + 2 i ) , ( - 1 - 2 i )

Step-by-step explanation:

Given equation as :

3 x² + 6 x +15 = 0

The value of x fro the quadratic equation a x² + b x + c = 0 is obtained as

x = $\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$

So , from given eq , the value of x is now obtain as

x = $\frac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}$

Or, x = $\frac{-6\pm \sqrt{6^{2}-4\times 3\times 15}}{2\times 3}$

Or, x = $\frac{\sqrt{-144} }{6}$

∴ x = ( - 1 + 2 i ) , ( - 1 - 2 i )

Hence The solution of given equation is ( - 1 + 2 i ) , ( - 1 - 2 i ) Answer

6 0

3 years ago

In △ABD, altitude AC¯¯¯¯¯ intersects the right angle of triangle ABD at vertex A. BC=4.2 in. and CD=9.6 in..

Ugo [173]

Answer:

AC = 6.35 in.

Step-by-step explanation:

BC times CD

4.2(9.6) = 40.32

The square root of 40.32 = 6.3498031465550174172038778087342

<u>Round your answer to the nearest hundredth</u>

AC = 6.35 in.

7 0

2 years ago

Can someone answer the 3 questions that aren’t filled in please?

blsea [12.9K]

You had mistakes, so I did all of them.

9) -6(1 + 11b) = -6 - 66b

10) -10(a - 5) = -10a + 50

11) -3(1 + 2v) = -3 - 6v

12)-4(3x + 2) = -12x - 8

13) (3 - 7k)*-2 = -2 * (3 - 7k) = -6 + 14k

14) -20(8x + 20) = -160x - 400

15) (7 + 19b)*-15 = -15(7 + 19b) = -105 - 285b

16) (x + 1) * 14 = 14(x + 1) = 14x + 14

6 0

3 years ago