2 years ago

Explain how to solve one absolute value equation by writing it as two equations.

1 answer:

5 0

If you have
|a|=b, then solve for the variable in euations
a=b and a=-b
for ineqalities, it is much trickier

for
|a|>b, assume a>b and a<-b
for
|a|<b, asssume -b<a<b

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three trigonometric functions for a given angle are shown below csc theta = 13/12, sec theta = -13/5, cot theta = -5/12 what are

goldenfox [79]

We have that
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12

we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13

sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13

sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant

therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12

the answer is
point (-5,12)

see the attached figure