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kotykmax [81]
3 years ago
5

How many solutions does the equation have

Mathematics
1 answer:
Bess [88]3 years ago
4 0
There is only one answer to this equation. h=3/4
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What is the correct answer for this question
ioda

Answer:

2 option I think, if I'm wrong so sorry ;(

Step-by-step explanation:

5 0
2 years ago
You want to buy three books that are on sale at 20% off. The original prices of the books are $2.50, $4.95, and $6.00. How much
Anon25 [30]

First add the prices of the original books.

2.5+4.95+6=11.45

Find 20% of 11.45

=2.29

Therefore I saved $2.29

8 0
3 years ago
Graph the function represented in the table on the coordinate plane.
Umnica [9.8K]
First find out the function for the given table.
Find the slope.
m= (y2-y1)/(x2-x1)
m=(-1-(-3)) / (-1-(-2))
m=(-1+3) / (-1+2)
m=2/1
m=2
Now equation of line:
y-y1=m(x-x1)
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y+3=2(x+2)
y+3=2x+4
y=2x+1
Now plot these points on the graph, we get the attached graph.

7 0
2 years ago
Read 2 more answers
A bucket that weighs 6 lb and a rope of negligible weight are used to draw water from a well that is 80 ft deep. The bucket is f
zaharov [31]

Answer:

3200 ft-lb

Step-by-step explanation:

To answer this question, we need to find the force applied by the rope on the bucket at time t

At t=0, the weight of the bucket is 6+36=42 \mathrm{lb}

After t seconds, the weight of the bucket is 42-0.15 t \mathrm{lb}

Since the acceleration of the bucket is the force on the bucket by the rope is equal to the weight of the bucket.

If the upward direction is positive, the displacement after t seconds is x=1.5 t

Since the well is 80 ft deep, the time to pull out the bucket is \frac{80}{2}=40 \mathrm{~s}

We are now ready to calculate the work done by the rope on the bucket.

Since the displacement and the force are in the same direction, we can write

W=\int_{t=0}^{t=36} F d x

Use x=1.5 t and F=42-0.15 t

W=\int_{0}^{36}(42-0.15 t)(1.5 d t)

=\int_{0}^{36} 63-0.225 t d t

=63 \cdot 36-0.2 \cdot 36^{2}-0=3200 \mathrm{ft} \cdot \mathrm{lb}

=\left[63 t-0.2 t^{2}\right]_{0}^{36}

W=3200 \mathrm{ft} \cdot \mathrm{lb}

4 0
2 years ago
The rectangle shown has a perimeter of 154 cm and the given area. Its length is 5 more than five times its width. Write and solv
Andreyy89

Answer:

2(L+W) = 34

L + W = 17

.

L*W = 52

.

L = 2W+5

.

2L + 2W = 34

L - 2W = 5

--------------- add

3L = 39

L = 13

8 0
3 years ago
Read 2 more answers
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