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Viktor [21]
4 years ago
15

Solve 30x -12,000 less than or equal to 980

Mathematics
1 answer:
Lyrx [107]4 years ago
6 0

Answer:

\large\boxed{x\leq432\dfrac{2}{3}\to x\in\left(-\infty,\ 432\dfrac{2}{3}\right]}

Step-by-step explanation:

30x-12,000\leq980\qquad\text{add 12,000 to both sides}\\\\30x-12,000+12,000\leq980+12,000\\\\30x\leq12,980\qquad\text{divide both sides by 30}\\\\x\leq\dfrac{12,980}{30}\\\\x\leq\dfrac{1,298}{3}\\\\x\leq432\dfrac{2}{3}

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Find the area of a circle of radius 4 cm.​
Mnenie [13.5K]

Answer:

Step-by-step explanation:

Area of a circle=πr²

A=π*4²

A=16π

A=50.27 ( rounded to nearest 100th)

4 0
4 years ago
Consider the differential equation x^2 y''-xy'-3y=0. If y1=x3 is one solution use redution of order formula to find a second lin
Anastasy [175]

Suppose y_2(x)=y_1(x)v(x) is another solution. Then

\begin{cases}y_2=vx^3\\{y_2}'=v'x^3+3vx^2//{y_2}''=v''x^3+6v'x^2+6vx\end{cases}

Substituting these derivatives into the ODE gives

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Let u(x)=v'(x), so that

\begin{cases}u=v'\\u'=v''\end{cases}

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\dfrac{\mathrm d}{\mathrm dx}[x^5u]=0

Integrate both sides with respect to x:

\displaystyle\int\frac{\mathrm d}{\mathrm dx}[x^5u]\,\mathrm dx=C

x^5u=C\implies u=Cx^{-5}

Solve for v:

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\dfrac{y_2}{x^3}=-\dfrac{C_1}4x^{-4}+C_2\implies y_2=C_2x^3-\dfrac{C_1}{4x}

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3 0
3 years ago
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photoshop1234 [79]

Answer:

10

Step-by-step explanation:

5/x = 4/8

Cross multiply

4*x = 5*8

4x = 40

x = 10

Answer is 10

You are correct

3 0
3 years ago
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(0,-3)
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