All categories

2 years ago

The slope of line parallel to the line y = 9x + 14 is

Mathematics

1 answer:

sergiy2304 [10]2 years ago

5 0

Answer:

Its 9

Step-by-step explanation:

The number next to the x its the slope when you have that form of a line

You might be interested in

at a hardware store, 5 gallons of paint and 5 paintbrushes cost $120, while 2 gallons of paint and 6 paintbrushes cost $64. Find

Katyanochek1 [597]

Well the answer is 9 for 1 paintbrush

7 0

2 years ago

Need this answered today, will give brainliest: The Steelers are on the Cowboys’ fifteen-yard line. Use your place value mat or

Nata [24]

Answer: 15 yards

Step-by-step explanation:

From the question, we have been informed that the Steelers are on the Cowboys' fifteen-yard line. Using the place value mat to calculate how much farther Steelers need to travel to score a touchdown goes thus:

Since the play is 15 yards from the Cowboys end-zone, therefore Steelers need to travel 15 yards for them score a touchdown.

5 0

3 years ago

It is assumed that the test results for a class follow a normal distribution with a mean of 78 and a standard deviation of 36. I

HACTEHA [7]

Answer:

0.7143

- You know the minimum possible grade of the student

- You want to find out the probability that that grade which is greater than 72 is also greater than 84

- Expect the answer to be 0.7143

- The explanation/steps is given below

- The answer seems (and is) reasonable. You only created a new lower limit.

Step-by-step explanation:

Distribution Type: Normal

Mean: 78

Standard deviation: 36

Range of marks: [78 - 36], [78 + 36] = [42 to 114]

If you know that a student's grade is greater than 72, what is the probability that it's greater than 84?

In this case, the full probability level is between 72 and the upper limit of 114 (instead of between 42 and 114). First, find the fraction of this probability.

[114 - 72] ÷ [114 - 42] = 42/72 = 0.5833

So, the probability of a student's mark falling between 72 and 114 is 0.5833.

Now making this a whole interval, 114 - 72 = 42

What fraction of this interval of 42 will bear marks between 84 and 114?

[114 - 84] = 30

30/42 = 0.7143

Because of the first part of the question "If you know (are sure) that a student's grade is greater than 72...", your answer stops at 0.7143, since 72 was used as the lower limit.

8 0

2 years ago

344531 to the nearest tenth

sineoko [7]

Rounded to the nearest tenth the number doesn't change Fam

4 0

3 years ago

A random sample of 150 men found that 88 of the men excercise regularly, while a random sample 200 women found that 130 of the w

melamori03 [73]

Answer:

The hypothesis is:

H₀: $p_{X}-p_{Y}=0$ .

Hₐ: $p_{X}-p_{Y}$ .

Step-by-step explanation:

Let X = number of men who exercise regularly and Y = number of women who exercise regularly.

The information provided is:

$n_{X}=150\\X=88\\n_{Y}=200\\Y=130$

Compute the sample proportion of men and women who exercise regularly as follows:

$\hat p_{X}=\frac{X}{n_{X}}=\frac{88}{150}=0.587$

$\hat p_{Y}=\frac{Y}{n_{Y}}=\frac{130}{200}=0.65$

The random variable X follows a Binomial distribution with parameters n = 150 and $\hat p_{X}=0.587$ .

The random variable Y also follows a Binomial distribution with parameters n = 200 and $\hat p_{Y}=0.65$ .

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\hat p=p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$

So, the sampling distribution of the proportion of men and women who exercise regularly follows a Normal distribution.

A two proportion z-test cab be performed to determine whether the proportion of women is more than men who exercise regularly.

The hypothesis for this test cab be defined as:

H₀: The proportion of women is same as men who exercise regularly, i.e. $p_{X}-p_{Y}=0$ .

Hₐ: The proportion of women is more than men who exercise regularly, i.e. $p_{X}-p_{Y}$ .

6 0

3 years ago

Read 2 more answers