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oksano4ka [1.4K]
3 years ago
13

A new American graduate is contemplating buying a Japanese, German, or an American car. No matter the type of car, he plans to b

uy a new one at the end of 8 years. Japanese car will cost $30,000 and have a fuel usage of 23 Miles Per gallon (mpg) for the first 2 years, and will decrease by 3% per year thereafter. Repair cost will start at $700 per year, and increase by 3% per year. At the end of year 8, the car can be sold for $5000. Insurance cost will be $700 for the first year, increasing by 2% per year thereafter. Page 2 of 3 Examiners: Dr. A. Afful-Dadzie, and Dr. A. Karimu A German car will cost $45,000 and have fuel usage of 21mpg for the first 5 years, and decrease by 1% thereafter to year 8. Repair cost will start at $1000 in year 1 and increase by 4% per year. It will have a salvage value of $7000 at the end of year 8. Insurance cost will be $850 the first year, increasing by 2% per year thereafter. The American car will cost $35,000 and have fuel usage of 20mpg for the first 3 years, and will decrease by 3% per year thereafter. Repair cost will be $800 in year 1, increasing by 4% per year thereafter. Being an American, the graduate will price the pride of owning an American car at $0.4 for every 20 miles driven, increasing by 2% per year. Insurance cost will be $800 per year increasing by 2.2% per year. The car can be sold for $5500 at the end of year 8. If the graduate anticipates driving 150000 miles by the end of year 8 and the average interest rate is expected to remain at 5% per year, which car is economically affordable based on present worth analysis? Assume fuel cost will be $3 per gallon in year 1 and increase by an average of 2% per year. Show all your workings. (20 marks)
Mathematics
1 answer:
Svetach [21]3 years ago
6 0

Answer:

The best option is to buy Japanese Car.

Step-by-step explanation:

Fuel usage per year is 150000/ 8 = 18750 miles per year

Fuel cost (year 1 -8) = $3.0, $3.06, $3.12, $3.18, $3.25, $3.312, $3.38, $3.5

Japanese Car:

Fuel usage 18750 / 23 = 815 * $3 = $2446  

Fuel charges (year 1 -8) = $2445, $2494, $2623, $2758. $2900, $3050, $3207, $3372

Repair Cost (year 1 - 8) = $700, $721, $742, $764, $787, $811, $835, $860

Insurance cost (Year 1 - 8) = $700, $714, $728, $742, $757, $772, $788, $804

Present value of cost at 5% = 24674.07

Cost of car is $30,000

Total cost = $54674.07

Amercian Car:

Cost $35,000

Fuel usage 18750/20 = 937.5 * $3 per gallon = $2812.5.

Fuel charges (year 1 -8) = $2812, $2913, $2986, $3011. $3098, $3124, $3176, $3208

Repair Cost (year 1 - 8) = $800, $894, $921, $978, $1109, $1176, $1207, $1301

Insurance cost (Year 1 - 8) = $800, $827, $876, $898, $908, $932, $954, $934

Present value of cost at 5% = 25302.18

Cost of car is $35,000

Total cost = $60302.

German Car:

Cost = $45,000

Fuel usage 18750 / 21 = 892 * $3 = $2678  

Fuel charges (year 1 -8) = $2679, $2732, $2786, $2842. $2899, $2987, $3077, $3171

Repair Cost (year 1 - 8) = $1000, $1040, $1081, $1124, $1169, $1216, $1265, $1316

Insurance cost (Year 1 - 8) = $850, $867, $884, $902, $920, $938, $957, $976

Present value of cost at 5% = 27105.73

Cost of car is $45,000

Total cost = $72105.

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The solution to the given question will be:-

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B) The sum of a number, n, and 6.05 is 12.4. What is n: n = 6.35

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<h3>What is an expression?</h3>

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division

A) If a number, n, divided by 8 equals 2.5, what is n?

n / 8 = 2.5

n = 8 x 2.5 = 20

B) The sum of a number, n, and 6.05 is 12.4. What is n?

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n = 12.4 - 6.05 = 6.35

C)  Stacy is one-fourth as old as her mother. If Stacy's mother is

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(1 / 4) M_{age} = S_{age}

S_{age}  =  ( 36 / 4)

S_{age}  =  9 years

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