Answer:
The short answer is there isn’t.
Start by writing each of these as an expression:
x * y = 60
x + y = 7
Next, solve each for the same variable; in this case, y:
(x * y) / x = 60 / x
.: y = 60 / x
(x + y) - x = 7 - x
.: y = 7 - x
Next, replace y of the second expression to the first
y = 60 / x & y = 7 - x
.: 7 - x = 60 / x
Now, solve for x:
(7 - x) * x = (60 / x) * x
.: x * 7 - x^2 = 60
This is quadratic, so write it in the form of ax2 + bx + x = 0
(-1)x^2 + (7)x + (-60) = 0
.: a = -1, b = 7, c = -60
Finally solve for b:
x = (-b +- sqrt(b^2 - 4*a*c)) / 2a
.: x = (-7 +- sqrt(7^2 - 4*-1*-60)) / (2 * -1)
.: x = (-7 +- sqrt(49 - 240)) / -2
.: x = (-7 +- sqrt(-191)) / -2
The square root of a negative value is imaginary and thus there’s no real answer to this problem.
I'm pretty sure the answer is "A matrix separates rational and irrational numbers." (Note: I'm not that great with memorizing definitions, but I'm pretty sure.) Hope this helps :)
Answer:
The length of AB = 97/3 units
Step-by-step explanation:
We know that a rhombus is a quadrilateral whose four sides all have the same length.
Thus, the equation becomes
7x+2 = 4x+15
7x-4x = 15-2
3x = 13
x = 13/3
So, the length of CD = 7x+2 = 7(13/3)+2
= 91/3 + 2
= 97/3
And, the length of BC = 4x+15 = 4(13/3) + 15
= 97/3
- We already know that a rhombus is a quadrilateral whose four sides all have the same length.
Thus, the length of AB = 97/3 units
Answer:
B.
Step-by-step explanation:
The first number minus the 2nd number will close off the distance.
![\sqrt[6]{( \frac{2}{3}) ^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B6%5D%7B%28%20%5Cfrac%7B2%7D%7B3%7D%29%20%5E%7B2%7D%20%20%7D%20)
. The 6 is called the index and will replace the denominator in our power, and the 2 is the power on the base 2/3 which will replace the numerator in our final exponent. So what we have, rewritten, is this: 
. Of course that exponent can be reduced so what the actual exponent is is 1/3. Our final simplified expression is 