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3 years ago

Why does snow accumulate faster on grass then gravel ground?

Chemistry

2 answers:

ruslelena [56]3 years ago

5 0

Because stone holds heat longer.

brilliants [131]3 years ago

3 0

Snow tends to accumulate better on grass surfaces than concrete surfaces for several reasons. (1) A road surface is connected directly to the earth's surface. Vegetation and grass is more exposed to the cold air. It takes time for the soil temperatures do adjust to colder air temperatures.

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What is the molar mass of an unknown gas with a density of 2.00 g/L at 1.00 atm and 25.0 °C?

soldier1979 [14.2K]

Answer:

Explanation:Explanation:

Your starting point here will be the ideal gas law equation

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

∣

−−−−−−−−−−−−−−−

, where

- the pressure of the gas

- the volume it occupies

- the number of moles of gas

- the universal gas constant, usually given as

0.0821

atm

⋅

mol

⋅

- the absolute temperature of the gas

Now, you will have to manipulate this equation in order to find a relationship between the density of the gas,

, under those conditions for pressure and temperature, and its molar mass,

You know that the molar mass of a substance tells you the mass of exactly one mole of that substance. This means that for a given mass

of this gas, you can express its molar mass as the ratio between

and

, the number of moles it contains

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

∣

−−−−−−−−−−−−−

(

)

Similarly, the density of the substance tells you the mass of exactly one unit of volume of that substance.

This means that for the mass

of this gas, you can express its density as the ratio between

and the volume it occupies

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

∣

−−−−−−−−−−−

(

)

Plug equation

(

)

into the ideal gas law equation to get

⋅

Rearrange to get

⋅

Finally, use equation

(

)

to write

⋅

Convert the temperature of the gas from degrees Celsius to Kelvin then plug in your values to find

1.02

⋅

0.0821

atm

⋅

mol

⋅

(

273.15

)

0.990

atm

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

26.3 g mol

−

∣

−−−−−−−−−−−−−−−−

I'll leave the answer rounded to three

7 0

3 years ago

A piece of wood has a labeled length value of 63.2 cm. You measure its length three times and record the following data: 63.1 cm

Ulleksa [173]

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

Accepted value is true value.

Measured values is calculated value.

In the question given Accepted value (true value) = 63.2 cm

Given Measured(calculated values) = 63.1 cm , 63.0 cm , 63.7 cm

1) Percent error (%) for first measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.1 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.1 \right |}{63.2}\times 100$

$Percent error = \frac{0.1}{63.2}\times 100$

$Percent error = 0.00158\times 100$

Percent error = 0.158 %

2) Percent error (%) for second measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.0 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.0 \right |}{63.2}\times 100$

$Percent error = \frac{0.2}{63.2}\times 100$

$Percent error = 0.00316\times 100$

Percent error = 0.316 %

3) Percent error (%) for third measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.7 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.7 \right |}{63.2}\times 100$

$Percent error = \frac{\left | -0.5 \right |}{63.2}\times 100$

$Percent error = \frac{(0.5)}{63.2}\times 100$

$Percent error = 0.00791\times 100$

Percent error = 0.791 %

Percent error for each measurement is :

63.1 cm = 0.158%

63.0 cm = 0.316%

63.7 cm = 0.791%

7 0

4 years ago

WILL GIVE BRANLIEST TO FIRST ANSWER!!! I know the correct answer is either a or d. Can anyone explain which one it is and why? C

oee [108]

Answer: The IUPAC name of $CH_3C\equiv CCH_2CH_2Cl$ is 5-chloro-2-pentyne

Explanation:

1. First select the longest possible carbon chain. For the number of carbon atom, we add prefix as 'meth' for 1, 'eth' for 2, 'prop' for 3, 'but' for 4, 'pent' for 5, 'hex' for 6, 'sept' for 7, 'oct' for 8, 'nona' for 9 and 'deca' for 10.

2. The longest possible carbon chain should contain all the bonds and functional groups.

3. The numbering is done in such a way that the carbon containing the functional group or substituent gets the lowest number. Triple bond is given priority over substituent halogen.

4. The naming of alkane is done by adding the suffix -ane, alkene by adding the suffix -ene, alkyne.

Thus the IUPAC name of $CH_3C\equiv CCH_2CH_2Cl$ is 5-chloro-2-pentyne

4 0

3 years ago

Circle the atom with the largest atomic radius in each group

Dominik [7]

Answer:

The atomic radius increases down the group because more shell are added

Explanation:

Al >B

Na>Al

S>O

O>F

Br>Cl

Mg>Ca

4 0

3 years ago

Asap... define pure substances...

gtnhenbr [62]

A pure substance refers to an element or a compound that has no component of another compound or element. Pure substances are made of only one type of atom or molecule. Hydrogen gas and pure iron are examples of pure substances. Hydrogen consists of hydrogen atoms only while iron consists of only iron atoms. Mixing two pure substances results in a mixture. To separate the two, scientists use a method known as filtration. Mixtures can either be homogeneous or heterogeneous. The measure used to determine how pure a substance may be called purity. Besides hydrogen and iron, other pure substances include gold, diamonds, sugar, and baking soda.

3 0

3 years ago

Read 2 more answers