Given what we know, we can confirm that as with any experiment, the control variable will be the one that through each trial of the experiment, no matter how many times it is performed, stays constant.
<h3>What is a controlled variable?</h3>
- A variable that remains constant through an experiment.
- They are used to compare results to the normal condition.
- They are also used to isolate the changes to one factor at a time and thus know its exact effects on the outcome.
- This increases the accuracy of the data and the subsequent conclusion.
Therefore, we can confirm that if a variable stays constant through each phase and trial of an experiment, it is considered to be a controlled variable and is useful in order to increase the accuracy of the conclusion.
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Usually in this context you would be referring to the boiling and freezing point of a NaCl <em>solution</em> (saltwater) compared to pure H_{2}O. Sematics would be different for NaCl compound itself, you would say melting and boiling point for a solid substance- and the temperatures would be very, very radical (high).
The boiling point of pure water is 100 degrees C (212 F), and the freezing/melting point is below 0 degrees C (32 F). For a salt water solution, the boiling point is raised and the melting point is lowered. This means that water will stay liquid for an increased range of temperature. Depending on the amount of NaCl solute in the water, the boiling and melting points may change a few degrees.
The correct answer is H20.
In a chemical reaction, there are always two sides, the reactant side and the product side. The reactants are the elements that are reacting together. They are always written at the left side of a chemical equation, with a plus sign written in between two elements. The products are the new compounds that are formed from the reaction of reactants. They are always written at the right side of a chemical equation and a plus sign is used to join them if they are more than one. An arrow pointing to the products usually connect the two side of the equation. For the question give above, the reactant are CH4 and O2 and the products are CO2 and H2O.
Answer:
0.010g of C-14 would be later after 50,000 years
Explanation:
The kinetics of radioactive decay follows the equation:
Ln (N / N₀) = -kt
<em>Where N could be taken as mass after time t, </em>
<em>N₀ initial mass = 4.30g;</em>
k is rate constant = ln 2 / t(1/2)
<em>= ln 2 / 5730years = 1.2097x10⁻⁴ years ⁻¹</em>
<em />
Replacing:
Ln (N / 4.30g) = -1.2097x10⁻⁴ years ⁻¹ * 50000 years
N / 4.30 = 2.36x10⁻³
N =
<h3>0.010g of C-14 would be later after 50,000 years</h3>
