Answer:
<em><u>Percent volume-volume (%(v/v)) = 100 x (volume of solute / volume of solution)</u></em>
<em><u>Percent volume-volume (%(v/v)) = 100 x (volume of solute / volume of solution)ex. 20 ml of methanol dissolved in enough water to make 200 ml of solution would result in a 10 % methanol solution</u></em>
<em><u>Percent volume-volume (%(v/v)) = 100 x (volume of solute / volume of solution)ex. 20 ml of methanol dissolved in enough water to make 200 ml of solution would result in a 10 % methanol solution-the units may be any units of volume you chose - as long as they are consistent</u></em>
<em><u>Percent volume-volume (%(v/v)) = 100 x (volume of solute / volume of solution)ex. 20 ml of methanol dissolved in enough water to make 200 ml of solution would result in a 10 % methanol solution-the units may be any units of volume you chose - as long as they are consistent-this concentration unit is most often used when mixing two liquids</u></em>
1) Calculate the number of moles of Cu SO4 . 5H20 by dividing the specified mass by the molar mass.
2) The ratio of production given by the equation is 1 mol of Cu SO4 . 5 H2O to 1 mol of Cu SO4=> 1:1, meaning that the number of moles of Cu SO4 produced is the same number of moles of Cu SO4.5H20 heated.
3) Finally mutiply the number of moles of Cu SO4 by its molar mass and there you have the mass of Cu SO4 produced.
MARK ME BRAINLIEST PLEASE!!!!!!!!
It’s Tetracarbon dioxide :)
Answer:
Particles would move more freely, while still staying close together depending on the shape of the liquid
Explanation:
Melting is the process of going from a solid to a liquid due to the increase in heat/energy. This increase in heat/energy increases the speed at which the atoms within the object moves. Lets say we had an ice cube. While it is a cube, the particles inside the cube are slow and compact, staying close together.
When enough energy is gained, this makes the particles begin to move faster, gaining heat and energy which results in the ice cube melting and moving more freely than normal.