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Oliga [24]
3 years ago
11

How do you write 4410 in a proper scientific notation.

Mathematics
1 answer:
Korolek [52]3 years ago
3 0
Raise 10 to the power of the places that you move the decimal place to the left and multiply that with the mixed number created by moving the decimal place...

In this case we need to move the decimal point 3 places to the left so we will multiply by 10^3 so

4.41X10^3
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the scale model of a building is 5.4 feet tall. if the model is made out of tiny bricks each measuring 0.4 inch in height, how m
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13.5 bricks
is the answer if im correct

8 0
3 years ago
If two lines are cut by a transversal, the corresponding angles are equal in measure always, sometimes, never
Ivahew [28]
I would choose... sometimes
3 0
3 years ago
Read 2 more answers
A tire travels about 75 inches in one full rotation. What is the Demeter of the tire, to the nearest inch?
Gnoma [55]

Answer:

<h2><u>24 inches</u></h2><h2><u></u></h2>

Step-by-step explanation:

c = πd

75 = 3.14d

Divide both sides by 3.14

23.89 = d

Rounded

24 inches

5 0
2 years ago
In an alloy of gold and silver the ratio of the metals is 6:4. How much gold is there in 200 grams of this alloy?​
nexus9112 [7]

Answer:

120 gold is in the alloy

Step-by-step explanation:

G:S

6:4

6+4=10

200/10=20

20*6=120

Hope this helps!

4 0
2 years ago
A 20.3 kg person climbs up a uniform ladder with negligible mass. The upper end of the ladder rests on a frictionless wall. The
VMariaS [17]

Answer:

Q = arctan(7.1739) = 82.06

Step-by-step explanation:

Given:

- The mass of the person m = 20.3 kg

- The distance traveled up the ladder s = 1.1 m

- The gravitational constant g = 9.8 m/s^2

- The coefficient of static friction u_s = 0.23

- Total length of the ladder

Find:

The minimum angle θ, that would allow the person to climb without ladder slipping

Solution:

- Taking moments about point of ladder and wall contact A to be zero:

                   -F_n,b*cos(Q)*4 - F_f*sin(Q)*4+ m*g*cos(Q)*2.6 = 0

- Taking Sum of vertical forces to be zero:

                    F_n,b - m*g = 0

                    F_n,b = m*g

- The frictional force F_f is given by:

                   F_f = u_s*F_n,b = u_s*m*g

- Plug the values back in:

                  - m*g*cos(Q)*4 + u_s*m*g*sin(Q)*4 - m*g*cos(Q)*2.6 = 0

Simplify:

                  4*cos(Q) + 2.6*cos(Q) = u_s*4*sin(Q)

                        6.6*cos(Q) = 4*u_s*sin(Q)

                               tan(Q) = 6.6 / 4*u_s

- Plug in the values:

                               tan(Q) = 6.6 / 4*0.23

                                    Q = arctan(7.1739) = 82.06

                   

                     

4 0
3 years ago
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