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Sindrei [870]
3 years ago
8

Select the correct answer.

Mathematics
1 answer:
Vikki [24]3 years ago
3 0

Answer:

the answer is A. 3225

Step-by-step explanation:

S₃₀ = 30/2 [ 2 x 6 + (30 - 1) x 7 ]

15 [ 12 + 29 x 7 ]

15 [ 12 + 203 ]

15 x 215

=3225

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Go step by step to reduce the radical. V240 Ovi try You must answer all questions above in order to submit.
Stolb23 [73]

Reducing the radical, we'll get:

\sqrt[]{240}\rightarrow\sqrt[]{16\cdot15}\rightarrow\sqrt[]{16}\cdot\sqrt[]{15}\rightarrow4\text{ }\sqrt[]{15}

The answer is:

4\text{ }\sqrt[]{15}

5 0
1 year ago
Help Plsss , Thanks
natulia [17]
A) 1 is greater
B) They are equal
C)1 is greater
4 0
4 years ago
True or False: A race car driver tested his car for time from 0 to 60 mph, and for 20 tests obtained a mean of 4.85 seconds with
sattari [20]

Answer:

The given statement is false.    

Step-by-step explanation:

We are given the following in the question:

95% confidence interval: (4.53,5.18)

Sample mean, \bar{x} = 4.85 seconds

Sample size, n = 20

Alpha, α = 0.05

Sample standard deviation, σ = 1.47 seconds

Degree of freedom = n - 1 = 19

95% Confidence interval:  

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 4 and}~\alpha_{0.01} = \pm 2.09

4.85 \pm 2.09(\dfrac{ 1.47}{\sqrt{20}} )\\\\ = 4.85 \pm 0.69 \\\\= (4.16 ,5.54)  

Thus, the calculated confidence interval is different from the given confidence interval.

Hence, the given statement is false.

6 0
4 years ago
LEAST COMMON MULTIPLE OF 27 , 48, 66
MrRissso [65]
27|\fbox3\\.\ 9|3\\.\ 3|3\\.\ 1|\\------------\\48|\fbox2\\24|2\\12|2\\.\ 6|2\\.\ 3\fbox3\\.\ 1|\\------------\\66|\fbox2\\33|\fbox3\\11|11\\.\ 1|\\=====================\\LCM(27;\ 48;\ 66)=3\times3\times3\times2\times2\times2\times2\times11=4,752\\\\Answer:\boxed{LCD(27;\ 48;\ 66)=4,752}

8 0
3 years ago
Read 2 more answers
How does the volume of a cylinder change when it’s diameter is doubled
zavuch27 [327]
Recallin that, the diameter is twice as long as the radius, namely the radius is half the diameter, so, if the diameter is doubled, the radius is also doubled.

\bf \textit{volume of a cylinder}\\\\
V=\pi r^2 h\quad 
\begin{cases}
r=radius\\
h=height\\
-----\\
r=\stackrel{doubled}{2r}
\end{cases}\implies V=\pi (2r)^2 h
\\\\\\
V=\pi (2^2r^2)h\implies V=\pi 4r^2 h\implies V=4~(\pi r^2 h)

notice, the new volume is 4 times (πr² h), namely 4 times the original.
8 0
3 years ago
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