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valentinak56 [21]
3 years ago
13

Why do althletes stretch before a game

Mathematics
2 answers:
Tems11 [23]3 years ago
7 0

Answer:

Here's the reasons why it's important to stretch before and after a workout. When it comes to pre-workout stretching, stretching before a workout helps your body to become more pliable, which decreases your risk for injury. ... The main muscles groups used during the session are the ones that need to stretch. And sometimes for example middle splits you might need to repair your hips to fake one because you didn't stretch to open the muscles up first not force them

Step-by-step explanation:

I hope you understood it. Good Luck

<u><em>Please mark me brainliest please!!</em></u>

alex41 [277]3 years ago
3 0

Answer:

so they dont get cramps or chairly horses

Step-by-step explanation:

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1000x8129= WILL MAKR BRANLYEST
8_murik_8 [283]

Answer:

it is 8,129,000

Step-by-step explanation:

1000x8129 = 8,129,000

8 0
2 years ago
Use the quadratic formula to solve 2x^2=5x+6. Leave your answer in radical form. Show all of your work!
Westkost [7]

Answer:

In radical from 169/50 , 177/200

Step-by-step explanation:

Given:

2x^2=5x+6\\\\2x^2-5x-6=0\\\\Where, a=2 , b=-5 , c=-6

Find:

Value of x

Computation:

Using quadratic formula:

\frac{-b\±\sqrt{b^2-4ac} }{2a}\\\\By\ putting\ all\ value\\\\ \frac{-(-5)\±\sqrt{(-5)^2-4(2)(-6)} }{2(2)}\\\\ \frac{5\±\sqrt{25+48} }{4}\\\\ \frac{5\±8.54 }{4}\\\\\frac{5+8.54 }{4},\frac{5-8.54 }{4} \\\\3.38 , 0.885

Value of x 3.38 , 0.885

In radical from 169/50 , 177/200

8 0
3 years ago
Write a power function whose graph passes through the given points
KonstantinChe [14]
Y=(1.414)(1.46) to the power of x.

4 0
2 years ago
Answer? .............................
kumpel [21]

ANSWER TO QUESTION ONE IS   5  

5x2+5=15  

5-4=1

15x1=15

QUESTION 2

X = 20

IDK 3 :(

7 0
3 years ago
Find the derivative of 3e^y+x=y
Sindrei [870]

You have the following function:

y=3e^y+x

Derivate implictly the previous expression, as follow:

y^{\prime}=3e^yy^{\prime}+1

Where you have used that:

(e^y)^{\prime}=e^yy^{\prime}

Then, the implicit derivative of the given expression is:

y^{\prime}=3e^yy^{\prime}+1

Next, solve for y' as follow:

\begin{gathered} y^{\prime}-3e^yy^{\prime}=1 \\ (1-3e^y)y^{\prime}=1 \\ y^{\prime}=\frac{1}{1-3e^y} \end{gathered}

4 0
1 year ago
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