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Komok [63]
3 years ago
11

Factor out coefficient of variable for 4h-3

Mathematics
2 answers:
Dmitriy789 [7]3 years ago
5 0

Answer:  On factoring out coefficient of variable for (4h-3) we get:

4(h-\frac{3}{4})

Explanation:

Coefficient of the variable is the number which is multiplying with the variable. Generally coefficient is written before the variable for example: 2 is the coefficient of x in equation (2x+1).

Here in the given equation (4h-3) the coefficient of the variable 'h' is 4.

When we factor out  the coefficient of the variable 'h' from the given equation  we will get:

(4h-3)=4\times(h-\frac{3}{4})

natita [175]3 years ago
5 0
4 * (h - 3/4)
Just divide 4h and -3 by 4, then put the 4 outside the parentheses of the answer you got. Like above.
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Simplify. 12k - 6 + (3k)(4) Is it -6, 6, 24k + 6, or 24k - 6?
Effectus [21]
It's 24k-6

By order of operations, you do the multiplication first: 3k(4) = 12k

12k-6+12k now combine like terms

24k-6

Hope that helps




7 0
3 years ago
Complete the identity.<br> 1) sec^4 x + sec^2 x tan^2 x - 2 tan^4 x = ?
Alecsey [184]

Answer:

See Explanation

Step-by-step explanation:

<em>Question like this are better answered if there are list of options; However, I'll simplify as far as the expression can be simplified</em>

Given

sec^4 x + sec^2 x tan^2 x - 2 tan^4 x

Required

Simplify

(sec^2 x)^2 + sec^2 x tan^2 x - 2 (tan^2 x)^2

Represent sec^2x with a

Represent tan^2x with b

The expression becomes

a^2 + ab- 2 b^2

Factorize

a^2 + 2ab -ab- 2 b^2

a(a + 2b) -b(a+ 2 b)

(a -b) (a+ 2 b)

Recall that

a = sec^2x

b = tan^2x

The expression (a -b) (a+ 2 b) becomes

(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)

..............................................................................................................................

In trigonometry

sec^2x =1  +tan^2x

Subtract tan^2x from both sides

sec^2x - tan^2x =1  +tan^2x - tan^2x

sec^2x - tan^2x =1

..............................................................................................................................

Substitute 1 for sec^2x - tan^2x in (sec^2x -tan^2x) (sec^2x+ 2 tan^2x)

(1) (sec^2x+ 2 tan^2x)

Open Bracket

sec^2x+ 2 tan^2x ------------------This is an equivalence

(secx)^2+ 2 (tanx)^2

Solving further;

................................................................................................................................

In trigonometry

secx = \frac{1}{cosx}

tanx = \frac{sinx}{cosx}

Substitute the expressions for secx and tanx

................................................................................................................................

(secx)^2+ 2 (tanx)^2 becomes

(\frac{1}{cosx})^2+ 2 (\frac{sinx}{cosx})^2

Open bracket

\frac{1}{cos^2x}+ 2 (\frac{sin^2x}{cos^2x})

\frac{1}{cos^2x}+ \frac{2sin^2x}{cos^2x}

Add Fraction

\frac{1 + 2sin^2x}{cos^2x} ------------------------ This is another equivalence

................................................................................................................................

In trigonometry

sin^2x + cos^2x= 1

Make sin^2x the subject of formula

sin^2x= 1  - cos^2x

................................................................................................................................

Substitute the expressions for 1  - cos^2x for sin^2x

\frac{1 + 2(1  - cos^2x)}{cos^2x}

Open bracket

\frac{1 + 2  - 2cos^2x}{cos^2x}

\frac{3  - 2cos^2x}{cos^2x} ---------------------- This is another equivalence

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3 years ago
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Answer:

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Step-by-step explanation:

subtract 180 from 71 and you will get 109°

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