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Dennis_Churaev [7]

3 years ago

5

Write the standard form of the line that passes through the given points. Include your work in your final answer.

1 answer:

makvit [3.9K]3 years ago

8 0

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{3 - 5}{-2 - 1} = \frac{-2}{-3} = \frac{2}{3}$

y - y₁ = m(x - x₁)
y - 5 = ²/₃(x - 1)
  y - 5 = ²/₃(x) - ²/₃(1)
  y - 5 = ²/₃x - ²/₃
+ 5 + 5
y = ²/₃x + 4¹/₃
⁻²/₃x + y = ²/₃x - ²/₃x + 4¹/₃
⁻²/₃x + y = 4¹/₃
  -3(⁻²/₃x + y) = -3(4¹/₃)
-3(⁻²/₃x) - 3(y) = -13
  2x - 3y = -13

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Hi can anybody explain to me how to do this I'm kinda confused . 5×[5(-7)]

telo118 [61]

Answer:

5 × [5(-7)]

= 5 × (-35) ---- 5 × (-7) = -35

= -175

4 0

3 years ago

Simplify the following. (7+5i)^2−(3+2i)=

Ivahew [28]

Answer:

hope that will help you

7 0

3 years ago

FInd the length of a segment that has endpoints H(2,-3) and J(12,7)

N76 [4]

d =sqrt ((x2-x1)^2 +(y2-y1)^2)

sqrt((12-2)^2 +(7--3)^2)

sqrt(10^2+10^2)

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5 0

3 years ago

Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; $(x^2-4)^2y'' + (x + 2)y' + 7y = 0$

The above equation can be better expressed as:

$y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0$

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

$p(x) = \dfrac{(x+2)}{(x^2-4)^2} \$

$p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \$

$p(x) = \dfrac{1}{(x+2)(x-2)^2}$

Also;

$q(x) = \dfrac{7}{(x^2-4)^2}$

$q(x) = \dfrac{7}{(x+2)^2(x-2)^2}$

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

$\lim \limits_{x \to-2} (x+ 2) p(x) = \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{1}{(x-2)^2}$

$\implies \dfrac{1}{16}$

$\lim \limits_{x \to-2} (x+ 2)^2 q(x) = \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{7}{(x-2)^2}$

$\implies \dfrac{7}{16}$

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0

3 years ago

if the morning temperature started at -7 celsius but warmed during the day to 24 celsius . What is the temperature change

Murrr4er [49]

Answer:

31° change

Step-by-step explanation:

If we want to find the change between two numbers, we need to imagine it like a number line.

<-------------0------------->

Let's plot -7 and 24 on this number line.

<---------- $-7$ --0------------24>

If we want to get from -7 to 0, we increase by 7. To get from 0 to 24, we increase by 24.

So the total change is $7 + 24 = 31$ .

Hope this helped!

8 0

3 years ago