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Nikitich [7]
3 years ago
5

FInd the length of a segment that has endpoints H(2,-3) and J(12,7)

Mathematics
1 answer:
N76 [4]3 years ago
5 0

d =sqrt ((x2-x1)^2 +(y2-y1)^2)

sqrt((12-2)^2 +(7--3)^2)

sqrt(10^2+10^2)

sqt(100+100)

sqrt(200)

sqrt(100)sqrt(2)

10sqrt(2)

Choice B


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3 years ago
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pantera1 [17]
The perimeters of both are equal.
The side of the square is 12.
Therefore, its area equals to : 12² = 144

The rectangle base is 19.
Because it has the same perimeter as the square's, so rectangle perimeter is : 19 + 19 + side + side = 12 + 12 + 12 + 12
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= 2side = 48 - 38
= side of rectangle = 5
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8 0
3 years ago
Systems of equations, help please?
lord [1]
4x + 3y = 54 (1)
3x + 9y = 108 (2)

Multiply (1) by (-3)
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3x + 9y = 108
---------------------add
-9x  =  -54
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plug x = 6 into (1) to find y
4(6) + 3y = 54
24 + 3y = 54
3y = 30
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Answer
(6 , 10)

Hope it helps.
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