Let`s assume that points M, N and P are the touching points of those 3 circles:Then:Y M + M Z = 14,Z N + N X = 20X P + P Y = 18And also: M Z = ZN, Y M = P Y and N X = X P.Now we have a system of 3 equations ( Y M, M Z and X P are the radii of each circle ):Y M + M Z = 14M Z + X P = 20X P + Y M = 18 Y M - M Z = - 14+X P + Y M = 18 X P - M Z = 4Y M - M Z = - 14+M Z + X P = 20 X P - Y M = 6 /* ( - 1 )X P - M Z = 4 X P + Y M = - 6 X P - M Z = 4 Y M - M Z = - 2 Y M + M Z = 14 2 Y M = 12 => Y M = 6M Z - 6 = 2 => M Z = 8X P + 6 = 18
X P = 12
Radii of the circles are: 12, 8 and 6.
Answer:
10
Step-by-step explanation:
Given that:
Point X = (3, 2)
Point Y = (3, - 8)
Distance of point X to Y:
Distance = √(x2 - x1)^2 + (y2 - y1)^2
X1 = 3 ; y1 = 2 ; x2 = 3 ; y2 = - 8
Distance = √(3 - 3)^2 + (-8 - 2)
Distance = √(0)^2 + (-10)^2
Distance = √0 + 100
Distance = √100
Distance = 10
I forgot how to find the y intercept but the slope is -2/4
Your answer will be negative 2
Answer:
Whats the question?
Step-by-step explanation:
