All categories

3 years ago

What is the probability of randomly selecting one 9 from a standard deck of 52 cards?

Mathematics

1 answer:

Tpy6a [65]3 years ago

5 0

there are 4 9's in a deck so probability would be 4/52 reduced to 1/13

does the answer need to be in a different format?

You might be interested in

Can someone help me with this right answer only and please explain it too

sineoko [7]

Answer:

g(6) = 71

f(11) = 62

Step-by-step explanation:

Let's solve g(6) first

Plug 6 into x

g(6) = 2(6)^2 - 1

g(6) = 2(36) - 1

g(6) = 72 - 1

g(6) = 71

Now let's solve f(11)

f(11) = 5(11) + 7

f(11) = 55 + 7

f(11) = 62

<em>Thus, out answers are 71 and 62 respectively</em>

5 0

3 years ago

If f(x)=4x^2 and g(x)=x+1, find (fog)(x)

iren [92.7K]

Answer: The value of $(f_\circ g)(x)$ is $4(x+1)^2$ .

Step-by-step explanation:

Given: $f(x) = 4x^2 \text { and } g(x) = x+1$

To find: $(f_\circ g)(x)$

As we know it is composition function which means that g(x) function is in f(x) function.

So we have

$(f_\circ g) (x) = f[g(x)]$

$\Rightarrow( f_\circ g)(x)= f(g(x)) = 4(g(x))^2$

Now substitute the value of g(x) we get

$(f_\circ g)(x)= 4(x+1)^2$

Hence, the value of $(f_\circ g)(x)$ is $4(x+1)^2$ .

5 0

4 years ago

Which of these debts could possibly be forgiven under Chapter 7 bankruptcy? A. Credit Card Debt B. Child Support C. Alimony D. A

a_sh-v [17]

Chapter 7 - Bankruptcy is a very beneficial means for those facing severe financial uncertainty or debts. And even though it cannot remove all your liability, it can help you eliminate a number of arrears so you can begin working to reestablish your credit score. These are the debts which are not forgiven in Chapter 7: student loans, child support, alimony payments, majority of taxes you owe and secured or collateral debts.

So the answer is A. Credit Card. A credit card debt can be forgiven under chapter 7 because it is the main reason why people file for bankruptcy just to discharge their credit card balance.

4 0

3 years ago

Read 2 more answers

It is estimated that 75% of all young adults between the ages of 18-35 do not have a landline in their homes and only use a cell

Mademuasel [1]

Answer:

a) 75

b) 4.33

c) 0.75

d) $3.2 \times 10^{-13}$ probability that no one in a simple random sample of 100 young adults owns a landline

e) $6.2 \times 10^{-61}$ probability that everyone in a simple random sample of 100 young adults owns a landline.

f) Binomial, with $n = 100, p = 0.75$

g) $4.5 \times 10^{-8}$ probability that exactly half the young adults in a simple random sample of 100 do not own a landline.

Step-by-step explanation:

For each young adult, there are only two possible outcomes. Either they do not own a landline, or they do. The probability of an young adult not having a landline is independent of any other adult, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

75% of all young adults between the ages of 18-35 do not have a landline in their homes and only use a cell phone at home.

This means that $p = 0.75$

(a) On average, how many young adults do not own a landline in a random sample of 100?

Sample of 100, so $n = 100$

$E(X) = np = 100(0.75) = 75$

(b) What is the standard deviation of probability of young adults who do not own a landline in a simple random sample of 100?

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100(0.75)(0.25)} = 4.33$

(c) What is the proportion of young adults who do not own a landline?

The estimation, of 75% = 0.75.

(d) What is the probability that no one in a simple random sample of 100 young adults owns a landline?

This is P(X = 100), that is, all do not own. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 100) = C_{100,100}.(0.75)^{100}.(0.25)^{0} = 3.2 \times 10^{-13}$

$3.2 \times 10^{-13}$ probability that no one in a simple random sample of 100 young adults owns a landline.

(e) What is the probability that everyone in a simple random sample of 100 young adults owns a landline?

This is P(X = 0), that is, all own. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{100,0}.(0.75)^{0}.(0.25)^{100} = 6.2 \times 10^{-61}$

$6.2 \times 10^{-61}$ probability that everyone in a simple random sample of 100 young adults owns a landline.

(f) What is the distribution of the number of young adults in a sample of 100 who do not own a landline?

Binomial, with $n = 100, p = 0.75$

(g) What is the probability that exactly half the young adults in a simple random sample of 100 do not own a landline?

This is P(X = 50). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 50) = C_{100,50}.(0.75)^{50}.(0.25)^{50} = 4.5 \times 10^{-8}$

$4.5 \times 10^{-8}$ probability that exactly half the young adults in a simple random sample of 100 do not own a landline.

8 0

3 years ago

Plastic edging for flower beds comes in 50-foot rolls and costs $6.85 per roll. What is the cost to completely edge two rectangu

Klio2033 [76]

Answer:

The cost of edging the flower beds with roll is $41.10.

Step-by-step explanation:

Given,

dimension of rectangular flower bed :

length = 40 ft

width = 15 ft

dimension of circular flower bed :

diameter = 16 ft

cost of each roll = $6.85

We need to find the cost of roll used to cover completely rectangular and circular flower bed.

Solution,

Firstly we will find out the perimeter of the rectangular flower bed.

Since we know that the perimeter of rectangle is equal to twice the sum of its length and width.

framing in equation form, we get;

Perimeter = $2(40+15)=2\times55=110\ ft$

So the perimeter of 2 flower bed = $2\times110 =220\ ft$

Again we will find out the circumference of the circular flower bed.

And we know that the circumference of the circle is equal to pi multiplied with the diameter.

framing in equation form, we get;

Circumference = $\pi\times16=50.24\ ft$

Now the total edge for covering is equal to the sum of the perimeter of two flowerbed and circumference of one circular flower bed.

Total edge = $220+50.24=270.24\ ft$

Here also given that Plastic edging for flower beds comes in 50-foot per roll.

So we will find out the number of rolls required for edging.

For this we will use the unitary method.

50 ft = 1 roll

270.24 ft = number of roll

$\therefore number\ of\ rolls = \frac{270.24}{50}=5.40$

so we can say that there will be 6 rolls required for edging.

also given the cost of 1 roll is $6.85.

So the cost of 6 rolls = $6\times6.85=\$41.10$

Hence The cost of edging the flower beds with roll is $41.10.

6 0

3 years ago