For Part A.
The absolute value of vector A is
<span>|A | = 6
This is simply the square root of the sum of the squares of the coordinates.
For Part B
Do the same thing as in Part A
| B | = </span>√14
<span>
Part C
Simply subtract the corresponding elements resulting in
(-3, 2, 7)
Part D
</span>√62
<span>
Part E
Yes</span>
A class action law suit is one in which the courts allow several
people who all claim to have been harmed to pool grievances
and sue for damages on behalf of the group.
Answer:
Plate B.
Explanation:
If the direction of the electric field is from plate A to plate B, then this means that plate A is positively charged and plate B is negatively charged. If we are to move an electron between the plates, then we should place the electron on plate B, so the negatively charged electron can be attracted by the positive charges on plate A.
Answer:
Grounded used to carry the current in the normal conditions. while on the other side grounding is refer to that safety wire that is connected to the earth and currently does not transmit through it.
As grounding wire is referred to as safety wire hence it carries current only in an emergency like a short circuit.
Explanation:
A grounded conductor is referred to as one of the wire that needed in an electric circuit. it is basically a neutral conductor. It used to carry the current in the normal conditions. while on the other side grounding is refer to that safety wire that is connected to the earth and currently does not transmit through it.
As grounding wire is referred to as safety wire hence it carries current only in an emergency like a short circuit.
Answer:
4.2 J
Explanation:
Specific heat capacity: This is defined as the amount of a heat required to rise a unit mass of a substance through a temperature of 1 K
From specific heat capacity,
Q = cmΔt.............................. Equation 1
Where Q = amount of energy absorbed or lost, c = specific heat capacity of water, m = mass of water, Δt = Temperature rise.
Given: m = 1 g = 0.001 kg, Δt = 1 °C
Constant : c = 4200 J/kg.°C
Substitute into equation 1
Q = 0.001×4200(1)
Q = 4.2 J.
Hence the energy absorbed or lost = 4.2 J
