Let us first find out the radioactive constant of Phosphorus 32.
Radioactive constant, λ =
Here, is half life of phosphorus 32 = 14.3 days
λ =
The amount of 4 mg of phosphorus remain after 71.5 days can be found using the formula,
m=m₀e⁻(λt)
=
=
=
=
=
= 0.125 mg
The mass of 4 mg of phosphorus 32 remains after 71.5 days will be 0.125 mg.
It’s D A solution of two neurons or more elements
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Answer:
The magnetic field of Earth is created by currents of electricity that flow in the molten center.
Explanation:
Answer:
225 000 kilometers per second.
Answer:
The second system must be set in motion seconds later
Explanation:
The oscillation time, T, for a mass, m, attached to spring with Hooke's constant, k, is:
One oscillation takes T secondes, and that is equivalent to a 2π phase. Then, a difference phase of π/2=2π/4, is equivalent to a time t=T/4.
If the phase difference π/2 of the second system relative to the first oscillator. The second system must be set in motion seconds later