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Mrac [35]
3 years ago
8

Plz Help ima fail science... 25 points.

Physics
1 answer:
Neko [114]3 years ago
8 0
Search up criterion and look at the examples and then read it and then make it in your own words
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A sphere of radius 6cm is moulded into a thin cylindrical wire of length 32cm. Calculate the radius of the
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Answer:

4/3 pi R^3 = pi r^2 L     equating volume of sphere and wire

r = (4 R^3 / 3 * L)^1/2      solving for radius of wire

r = (4 * 6^3 / 3 * 32)^1/2

r = 9^1/2 cm = 3 cm = .03 meters

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2 years ago
A disk rotates around an axis through its center that is perpendicular to the plane of the disk. The disk has a line drawn on it
natka813 [3]

Answer:

t = \frac{\sqrt{\omega0^2+2*\theta*\alpha} -\omega0}{\alpha}

Explanation:

The rotated angle is given by:

\theta=\omega0*t+1/2*\alpha*t^2

Since this is a quadratic equation it can be solved using:

x=\frac{-b \± \sqrt{b^2-4*a*c}  }{2*a}

Rewriting our equation:

1/2*\alpha*t^2+\omega0*t-\theta=0

t = \frac{\±\sqrt{\omega0^2+2*\theta*\alpha} -\omega0}{\alpha}

Since \sqrt{\omega0^2+2*\theta*\alpha} >\omega0 we discard the negative solution.

t = \frac{\sqrt{\omega0^2+2*\theta*\alpha} -\omega0}{\alpha}

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