Equilibrium constant is defined as the ratio of concentration of the products raised to the power its stoichiometric coefficients to the concentration of reactants raised to power its stoichiometric coefficient. It is represented as $K_c$

For the general equation:

$aA+bB\rightleftharpoons cC+dD$

The equilibrium constant is represented as:

$K_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

For the given chemical equation:

$H_2(g)+CO_2(g)+10 kcal\rightleftharpoons H_2O(g)+CO(g)$

$K_c$ for this equation is given by:

$K_c=\frac{[H_2O][CO]}{[H_2][CO_2]}$

Concentration at equilibrium of

$H_2=2mol/L\\H_2O=4mol/L\\CO_2=5mol/L\\CO=4mol/L$

Putting values in above equation, we get:

$K_c=\frac{4\times 4}{2\times 5}\\K_c=0.8$

Hence, the equilibrium constant for the given chemical reaction is 0.8

6 0

3 years ago

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The substance that is doing the dissolving is referred to as?

ella [17]

Answer:

hi! I'm pretty sure your answer is solvent!

Explanation:

not 100% sure but I looked it up on google. solvent does the dissolving, solute is what is being dissolved, and a solution is the solvent + the solute. hope this helped!

7 0

4 years ago