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3 years ago

Please help. Will give brainliest

Chemistry

1 answer:

alexandr1967 [171]3 years ago

7 0

help in what??????????????????

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Evaporation of Cane Sugar Solutions. An evaporator is used to concentrate cane sugar solutions. A feed of 10 000 kg/d of a solut

Vera_Pavlovna [14]

Answer:

Weight of solution produced = 5135 kg

Amount of water removed = 4865 kg

Explanation:

For the balance of mass, the incoming mass of sugar must be equal to the outgoing mass. So, the incoming mass (mi) is 38% of 10000 kg

mi = 0.38x10000 = 3800 kg

The outgoing mass (mo) must be 3800 kg, and it is 74% of the total mass (mt)

mo = 0.74xmt

0.74xmt = 3800

mt = 3800/0.74

mt = 5135 kg

This is the mass of solution produced.

The amount of water removed (wr) is the amount of water incoming (wi) less the amount of water outgoing (wo). Both will be the total mass less the mass of sugar :

wi = 10000 - 3800 = 6200 kg

wo = 5135 - 3800 = 1335 kg

wr = wi - wo

wr = 6200 - 1335

wr = 4865 kg

8 0

4 years ago

We would like to estimate how quickly the non-uniformities in gas composition in the alveoli are damped out. Consider an alveolu

Vera_Pavlovna [14]

Answer: It will take 11.775 seconds.

Explanation: As a sphere with a diameter of 0.1 mm, the area of an alveolus is

A = 4.π.r²

r for an alveolus would be: r = 0.00005m or r = 5. $10^{-5}$ m

Finding the area:

A = 4.3.14.(5. $10^{-5}$ )²

A = 3.14. $10^{-8}$ m²

The concentration change is to be 90% of the final, so

c = 0.9.3.14. $10^{-8}$

c = 28.26. $10^{-9}$

The oxygen diffusivity is 2.4. $10^{-9}$ m²/s, that means in 1 second 2.4. $10^{-9}$ of oxygen spread in one alveolus area. So:

1 second = 2.4. $10^{-9}$ m²

t seconds = 28.26. $10^{-9}$ m²

t = $\frac{28.26.10^{-9} }{2.4.10^{-9} }$

t = 11.775s

For a concentration change at the center to be 90%, it will take 11.775s.

4 0

3 years ago

MEASUREMENT AND MATTER Interconverting temperatures in Celsius and Kelvins The metal osmium becomes superconducting at temperatu

nexus9112 [7]

Answer: $-272^0C$ .

Explanation:

Temperature of the gas is defined as the degree of hotness or coldness of a body. It is expressed in units like $^0C$ and $K$

These units of temperature are inter convertible.

We are given:

Temperature of the gas = $655mK=0.655K$ (1mK=0.001 K)

Converting this unit of temperature into $^0C$ by using conversion factor:

$(t-273.15)^0C=tK$

$273.15K=0^0C$

Thus $0.655K=(0.655-273.15)^0C=-272^0C$

Thus the temperature is $-272^0C$ .

5 0

3 years ago

Show work please osososs

Ilia_Sergeevich [38]

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8 0

3 years ago

What is the electron configuration for a calcium atom? 1s2, 2s2, 2p6, 3s2, 3p6, 4s2 1s2, 2s2, 2p6, 3s2, 3p6, 4s1 2s2, 2s2, 2p6,

Zarrin [17]

1s2,2s2, 2p6, 3s2,3p6,4s2

8 0

3 years ago

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