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allochka39001 [22]
2 years ago
7

Evaluate the following expression for y=-3 and k=2

Mathematics
1 answer:
Rudik [331]2 years ago
6 0

Answer:

{y}^{2}

Step-by-step explanation:

Move using the negative exponential rule

\frac{ {k}^{0} }{ { {y} }^{ - 2} }

{k}^{0}  {y}^{2}

Anything with 0 as an exponent is 1

1 {y}^{2}

{y}^{2}

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Mike wants to save $1,750 in the next 12 months. He plans to save $150 each month for the first 11 months.
podryga [215]

Answer:

$1650

Step-by-step explanation:

Based on the question, we don't need the information that Mike wants to save 1750 in 12 months.

We just need to focus on how he is saving 150 every month, for 11 months.

150*11=1650

He will save $1650 if he saves $150 every month for 11 months.

3 0
3 years ago
Read 2 more answers
A teacher has a bag of candy. If she gives every student in her class 4 pieces of candy, she is left with 48 pieces of candy. Ho
yawa3891 [41]
Well you can't actually find a number, but you can make an equation.
lets call the bag of candy x, and the number of students in the teachers class S.

she gives every student in her class 4 pieces, so to find that amount, we have to multiply the number of students in her class by 4, the pieces of candy. 4S

afterwards she has 48 pieces, which is the endpoint, x is the starting point because that's the amount of candy the teacher started with.

so your equation is x-4S=48, but the thing is, the question is looking for the amount of students she gave candy to, so we have to isolate S, or in easier words; put S on one side, and the numbers on the other.

so the equation is S=1/4x-12

6 0
3 years ago
95 divided by 4 and 34 divided by 2
MaRussiya [10]
95/4=\frac{95}{4}=23\frac{3}{4} or 23r3

and

34/2=\frac{34}{2}=17
5 0
3 years ago
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192+4(7a+6)<br><br> Pls<br> Help <br><br> Show ur work<br> (No spam)
horrorfan [7]

Answer:

192 + 4( 7a + 6 )

DISTRIBUTE  

192 + 28a + 24

ADD THE NUMBERS

216 + 28a     or        28a + 216

Step-by-step explanation:

U DON'T HAVE TO TYPE "DISTRIBUTE" and "ADD THE NUMBERS"

7 0
2 years ago
Which relation is a function? Question 3 options: {(1, 2); (1, 3); (1, 4); (1, 5)} {(1, 2); (2, 3); (3, 4); (4, 5)} {(1, 2); (3,
NeTakaya

To be a function for every identical x value it has to have a different Y value. If the set has two identical X values but they have different Y values it can't be a function.

The set that is a function is:

{(1, 2); (2, 3); (3, 4); (4, 5)}

4 0
2 years ago
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