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2 years ago

What is the square root of 56 in radical form

Mathematics

1 answer:

V125BC [204]2 years ago

7 0

$\sqrt{56} \\ \\ \sqrt{7*8} \\ \\ \sqrt{7*4*2} \\ \\ \sqrt{7*2*2*2} \\ \\ 2 \sqrt{7*2} \\ \\ 2 \sqrt{14}$

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Solve the equation for all real values of x.<br> cosxtanx - 2 cos x=-1

IceJOKER [234]

Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

<u>Step-by-step explanation:</u>

Here we have , $cosxtanx - 2 cos^2 x=-1$ . Let's solve :

⇒ $cosxtanx - 2 cos^2 x=-1$

⇒ $cosx(\frac{sinx}{cosx}) - 2 cos^2 x=-1$

⇒ $sinx = 2 cos^2 x-1$

⇒ $sinx = 2 (1-sin^2x)-1$

⇒ $sinx = 1-2sin^2x$

⇒ $2sin^2x+sinx-1=0$

By quadratic formula :

⇒ $sinx = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

⇒ $sinx = \frac{-1 \pm \sqrt{1^2-4(2)(-1)} }{2(2)}$

⇒ $sinx = \frac{-1 \pm3}{4}$

⇒ $sinx = \frac{1}{2} , sinx =-1$

⇒ $sinx = sin\frac{\pi}{6} , sinx = sin\frac{3\pi}{2}$

⇒ $x=\frac{\pi}{6} , x=\frac{3\pi}{2}$

But at $x=\frac{3\pi}{2}$ we have equation undefined as $cos\frac{3\pi}{2}=0$ . Hence only solution is :

⇒ $x=\frac{\pi}{6}$

Since , $sin(\pi -x)=sinx$

⇒ $x=\pi -\frac{\pi}{6} = \frac{5\pi}{6}$

Now , General Solution is given by :

⇒ $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$

Therefore , Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

3 0

2 years ago

Help me please ASAP !!!!!!!

kodGreya [7K]

Answer:

its A

PLS MARK AS BRAINLESS I MEAN BRAINLIEST :)

Step-by-step explanation:

6 0

1 year ago

A messenger earns 2640 per year and pays tax at the rate of 10k On a naira how much tax does he pay in the year

Marta_Voda [28]

Answer:

264 naira

Step-by-step explanation:

Given that:

Amount earned per year = 2460

Rate of interest paid : 10k per naira earned

Tax paid by messenger per year :

100k = 1 naira

10k = (100/10) = 0.1 naira

Hence 0.1 naira is paid as tax on every naira earned

Total amount paid on 2640 Naira :

Amount paid per naira * total amount earned

(0.1 * 2640) = 264 naira

5 0

2 years ago

A figure can be covered by 28 unit squares,without any gaps or overlaps.what is the area of the figure?

Tom [10]

Remember that the area of a square is just one of its sides squared. $A=s^2$
where
$A$ is the area of the square
$s$ is one of the sides of the square

Unit square is a square whose sides have length 1, so lets use our formula to find the volume of one unit square:
$A=s^2$
$A=1^2$
$A=1$
We now know that each one of the squares has area 1 unit squared. Since there are 28 unit square in our figure, we are going to multiply the area of a unit square by 28 to find the area of our figure:
Area of the figure= $28(1)=28$ units squared

We can conclude that the area of the figure is 28 units squared.

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2 years ago

Deside whether g(x) = 2x^3 - 7x^2 - 3x^-1

mina [271]

You haven’t actually ask a questionnnnnn?

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2 years ago