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faltersainse [42]
2 years ago
8

What is the slope of the line that passes through the points ( − 1 , − 7 ) (−1,−7) and ( 1 , − 13 ) (1,−13)? Write your answer i

n simplest form.
Mathematics
1 answer:
Paraphin [41]2 years ago
3 0

Answer:

y = -3x -10

Step-by-step explanation:

Slope-intercept formula: \frac{y_2-y_2}{x_2-x_1}

Find slope of  (−1, −7) and (1, -13)

\frac{y_2-y_2}{x_2-x_1}\\\\\\frac{-13-(-7)}{1-(-1)}\\\\\\frac{-6}{2}\\\\\-3

y = mx + b

y = -3x +b

y = -3x +b\\-7 = -3(-1) + b\\-7 = 3 +b\\-3   -3\\-10 = b

y = -3x -10

Hope this helps!

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2 years ago
A ribbon is 30cm long and it is cut into three pieces such that each piece is 2cm longer than the next. Represent this as an equ
Alisiya [41]

Answer:

Step-by-step explanation:

3 pieces such that each piece is 2 cm longer then the next...

x , x + 2, x + 4

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x = 24/3

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3 0
3 years ago
Read 2 more answers
Let v be an eigenvector of a matrix A with a corresponding eigenvalue ?=2. Find one solution x of the system Ax=v.
Murljashka [212]

Answer with explanation:

For, a Matrix A , having eigenvector 'v' has eigenvalue =2

 The order of matrix is not given.

It has one eigenvalue it means it is of order , 1×1.

→A=[a]

Determinant [a-k I]=0, where k is eigenvalue of the given matrix.

It is given that,

k=2

For, k=2, the matrix [a-2 I] will become singular,that is

→ Determinant |a-2 I|=0

→I=[1]

→a=2

Let , v be the corresponding eigenvector of the given eigenvalue.

→[a-I] v=0

→[2-1] v=[0]

→[v]=[0]

→v=0

Now, corresponding eigenvector(v), when eigenvalue is 2 =0

 We have to find solution of the system

→Ax=v

→[2] x=0

→[2 x] =[0]

→x=0, is one solution of the system.

5 0
3 years ago
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