The quadrants in which all the coordinates given are located is; As explained below.
<h3>How to Identify Quadrants in coordinates?</h3>
1) (2, 4) is located in Quadrant I where both x and y-values are positive.
2) (0, -3) is located in Quadrant II where x - values are positive but y-values are negative.
3) (-1, 1/2) is located in Quadrant IV.
4) (-2 1/2, -7) is located in Quadrant III where x and y values are both negative.
5) (0, 6) is located in Quadrant I where both x and y-values are positive.
6) (-5, 0) is located in Quadrant IV where x is negative but y is positive.
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Answer:
umm what
Step-by-step explanation:
For section 3.01 black, number 1 is correct, but number 2 is wrong.
When you raise an exponent to an exponent, you multiply the 2 exponents.
(x^4)^5 is x^20.
Number 3 is also right.
For 3.02, you use the interest formula. (1 + i/100)^t times x
x is the amount of money you have originally. i is the interest rate, t is the time.
1,500(1.03)^5 = 1738.91111145
$1738.91
For section 3.01 red in fractional exponents the numerator are the powers and the denominator is the root.
![\sqrt[4]{a^{3} } = a^{\frac{3}{4} }](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Ba%5E%7B3%7D%20%7D%20%20%3D%20a%5E%7B%5Cfrac%7B3%7D%7B4%7D%20%7D)
Answer:
Ax + Ay + 2A = 0 for any nonzero A, for example (A=1): x + y + 2 = 0
Step-by-step explanation:
The equation of a line is
Ax + By + C = 0
so we know that:
A*-3 + B*1 + C = 0
A*5 + B*-7 + C = 0
Let's subtract one from the other:
A*(-3 - 5) + B*(1 + -7) = 0
A*-8 + B*8 = 0
B*8 = A*8
B = A
Let's input B = A into the first two equations
A*-3 + A*1 + C = A*-2 + C = 0
A*5 + A*-7 + C = A*-2 + C = 0
checks out
C = 2A
So for any nonzero A the equation of
Ax + Ay + 2A = 0 produces a line passing between the points. Example would be
x + y + 2 = 0