1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
denpristay [2]
4 years ago
14

A multinational firm wants to estimate the average number of hours in a month that theiremployees spend on social media while on

the job. A random sample of 83 employees showedthat they spent an average of 21.5 hours per month on social media, with a standard deviationof 2.5. Construct and interpret a 95% confidence interval for the population mean hours spenton social media per month.

Mathematics
2 answers:
elena55 [62]4 years ago
7 0

Answer:

95% of the population spent between 16.8 hours to 26.2 hours on social media per month

Step-by-step explanation:

  1. subtracting 1 from sample size: 83-1= 82
  2. Note Mean=21.5 and standard deviation=2.5
  3. Subtracting confidence interval from 1 and dividing by 2: (1-0.95)/2=0.025
  4. At α=0.025 and dF=82,  the t-distribution table gives  1.984
  5. Divide standard deviation by square root of sample size: 21.5/√83= 2.36
  6. Multiplying answer in step 4 by answer in step 5: 2.36×1.984= 4.68
  7. For lower end: 21.5-4.68= 16.82
  8. for upper end: 21.5+4.68=26.18

sasho [114]4 years ago
4 0

Answer:

20.96-22.0378

Step-by-step explanation:

For a 95% confidence interval the z value is 1.96

The confidence interval will be given by

Mean±z×б/√n

21.5-1.96×2.5/√83 =20.96

21.5+1.96×2.5/√83 =22.0378

With 95% confidence the average hours spent by employees on social media per hour is between 20.96 to 22.0378 based on this sample data

You might be interested in
Emily had 75 buttons. She gave 15 buttons to Jake. What percent of the buttons did Emily give to Jake? My Answer:
frutty [35]
Since Emily gave 15 of her buttons out of 75, it's just 15/75 or 1/5 which is 20%
5 0
4 years ago
Find the maximum volume of a rectangular box that is inscribed in a sphere of radius r.
zvonat [6]

Answer:

The maximum volume of a box inscribed in a sphere of radius r is a cube with volume \frac{8r^3}{3\sqrt{3}}.

Step-by-step explanation:

This is an optimization problem; that means that given the constraints on the problem, the answer must be found without assuming any shape of the box. That feat is made through the power of derivatives, in which all possible shapes are analyzed in its equation and the biggest -or smallest, given the case- answer is obtained. Now, 'common sense' tells us that the shape that can contain more volume is a symmetrical one, that is, a cube. In this case common sense is correct, and the assumption can save lots of calculations, however, mathematics has also shown us that sometimes 'common sense' fails us and the answer can be quite unintuitive. Therefore, it is best not to assume any shape, and that's how it will be solved here.

The first step of solving a mathematics problem (after understanding the problem, of course) is to write down the known information and variables, and make a picture if possible.

The equation of a sphere of radius r is x^2 + y^2 + z^2=r^2. Where x, y and z are the distances from the center of the sphere to any of its points in the border. Notice that this is the three-dimensional version of Pythagoras' theorem, and it means that a sphere is the collection of coordinates in which the equation holds for a given radius, and that you can treat this spherical problem in cartesian coordinates.

A box that touches its corners with the sphere with arbitrary side lenghts is drawn, and the distances from the center of the sphere -which is also the center of the box- to each cartesian axis are named x, y and z; then, the complete sides of the box are measured  2x,  2y and 2z. The volume V of any rectangular box is given by the product of its sides, that is, V=2x\cdot 2y\cdot 2z=8xyz.

Those are the two equations that bound the problem. The idea is to optimize V in terms of r, therefore the radius of the sphere must be introduced into the equation of the volumen of the box so that both variables are correlated. From the equation of the sphere one of the variables is isolated: z^2=r^2-x^2 - y^2\quad \Rightarrow z= \sqrt{r^2-x^2 - y^2}, so it can be replaced into the other: V=8xy\sqrt{r^2-x^2 - y^2}.

But there are still two coordinate variables that are not fixed and cannot be replaced or assumed. This is the point in which optimization kicks in through derivatives. In this case, we have a cube in which every cartesian coordinate is independent from each other, so a partial derivative is applied to each coordinate independently, and then the answer from both coordiantes is merged into a single equation and it will hopefully solve the problem.

The x coordinate is treated first: \frac{\partial V}{\partial x} =\frac{\partial 8xy\sqrt{r^2-x^2 - y^2}}{\partial x}, in a partial derivative the other variable(s) is(are) treated as constant(s), therefore the product rule is applied: \frac{\partial V}{\partial x} = 8y\sqrt{r^2-x^2 - y^2}  + 8xy \frac{(r^2-x^2 - y^2)^{-1/2}}{2} (-2x) (careful with the chain rule) and now the expression is reorganized so that a common denominator is found \frac{\partial V)}{\partial x} = \frac{8y(r^2-x^2 - y^2)}{\sqrt{r^2-x^2 - y^2}}  - \frac{8x^2y }{\sqrt{r^2-x^2 - y^2}} = \frac{8y(r^2-2x^2 - y^2)}{\sqrt{r^2-x^2 - y^2}}.

Since it cannot be simplified any further it is left like that and it is proceed to optimize the other variable, the coordinate y. The process is symmetrical due to the equivalence of both terms in the volume equation. Thus, \frac{\partial V}{\partial y} = \frac{8x(r^2-x^2 - 2y^2)}{\sqrt{r^2-x^2 - y^2}}.

The final step is to set both partial derivatives equal to zero, and that represents the value for x and y which sets the volume V to its maximum possible value.

\frac{\partial V}{\partial x} = \frac{8y(r^2-2x^2 - y^2)}{\sqrt{r^2-x^2 - y^2}} =0 \quad\Rightarrow r^2-2x^2 - y^2=0 so that the non-trivial answer is selected, then r^2=2x^2+ y^2. Similarly, from the other variable it is obtained that r^2=x^2+2 y^2. The last equation is multiplied by two and then it is substracted from the first, r^2=3 y^2\therefore y=\frac{r}{\sqrt{3}}. Similarly, x=\frac{r}{\sqrt{3}}.

Steps must be retraced to the volume equation V=8xy\sqrt{r^2-x^2 - y^2}=8\frac{r}{\sqrt{3}}\frac{r}{\sqrt{3}}\sqrt{r^2-\left(\frac{r}{\sqrt{3}}\right)^2 - \left(\frac{r}{\sqrt{3}}\right)^2}=8\frac{r^2}{3}\sqrt{r^2-\frac{r^2}{3} - \frac{r^2}{3}} =8\frac{r^2}{3}\sqrt{\frac{r^2}{3}}=8\frac{r^3}{3\sqrt{3}}.

6 0
3 years ago
NEED HELP!!!!<br><br> Please
AnnZ [28]

Answer:

# 1,3 and 6

Step-by-step explanation:

4 0
3 years ago
In testing the lethal concentration of a chemical found in polluted water. it is found that a certain concentration will kill 20
sasho [114]

Answer:

a) 0.1091

b) 0.9994

c) 0.5886

Step-by-step explanation:

X = the number of fish out of 20 that die after 24 hours

x = 0, 1, 2, . . . , 20

X~ Binomial (n= 20, p =0.20)

P(14 survive) = P(X = 6)

= nC_r p^r q^{n-r}= 20C_6 0.2^6\times0.8^{14}=0.1091

Similarly we can find out

P(at least 10 survive) = P( X <= 10 ) = (Using technology) = 0.9994

P(at most 16 will survive) = P(X <= 16) = (Using technology) = 0.5886

7 0
3 years ago
A school custodian discovered a leak in a water pipe. The custodian found that 1920 fluid ounces of water leaked out. How many g
shtirl [24]
1920 fL/128G
= 15 Gallons
8 0
4 years ago
Read 2 more answers
Other questions:
  • Julian jogs 2 kilometers east, 4 kilometers north, and then 7 kilometers west
    8·1 answer
  • A recent newspaper article reported on​ Americans' eating habits. The article reported that only about one third of American adu
    14·1 answer
  • The LCM includes only the common factors of two terms<br> True<br> False
    7·2 answers
  • Find the point that partitions a segment AB where A (-2, -6) and B (6, 12) into two equal parts.
    9·1 answer
  • MathsWatch
    9·1 answer
  • (5m-2n) (25m^2 + 10mn + 4n^2)
    10·1 answer
  • Problem
    13·2 answers
  • Pleasee help meeeeeee
    6·1 answer
  • Use the muliplier method to increase 88 pound by 14% show your working
    9·1 answer
  • In scientific notation, 8,700 is written:
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!