Answer:
Step-by-step explanation:
Circle is centred at (0, -2)
-> h = 0 & k = - 2
radius of the circle (r) = y-coordinate of the center = - 2
Equation of circle in standard form is given as:
Plugging the values of h, k and r in the above equation, we find:
![(x-0)^2 +[y-(-2)]^2 = (-2)^2](https://tex.z-dn.net/?f=%28x-0%29%5E2%20%2B%5By-%28-2%29%5D%5E2%20%3D%20%28-2%29%5E2)
This is the required equation of circle.
Answer:
<u>Given rhombus ABCD with</u>
- m∠EAD = 67°, CE = 5, DE = 12
<u>Properties of a rhombus:</u>
- All sides are congruent
- Diagonals are perpendicular
- Diagonals are angle bisectors
- Diagonals bisect each other
<u>Solution, considering the above properties</u>
- 1. m∠AED = 90°, as angle between diagonals
- 2. m∠ADE = 90° - 67° = 23° as complementary of ∠EAD
- 3. m∠BAE = 67°, as ∠BAE ≅ ∠EAD
- 4. AE = CE = 5, as E is midpoint of AC
- 5. BE = DE = 12, as E is midpoint of BD
Answer:
there is no intercept
Step-by-step explanation:
Answer:
The answer is B
Step-by-step explanation:
