Answer:
We want to craft:
a/b and c/d
where a, b, c and d can be 2, 3, 4 and 5.
Such that the distance in the number line between these two numbers is maximized.
Then we want one number to be really small, and the other to be really large.
Remember two things:
for numbers like a/b.
if a is smaller than b, then a/b is smaller than 1.
Now, if a is larger than b, then a/b is larger than 1.
And two things,
1/10 = 0.1
10/1 = 10
So when the numerator is larger, the distance displaced in the number line is larger.
Then we want to have:
a number where the numerator is the largest option and the denominator is the smallest option:
a/b = 5/2
And the two remaining options in such way that the numerator is smaller than the denominator:
c/d = 3/4.
The distance between these two numbers is:
D = 5/2 - 3/4 = 10/4 - 3/4 = 7/4.
Answer:
18
Step-by-step explanation:
9 + 18 = 27
9 x 2 = 18
Answer: 3 tickets left
Step-by-step explanation:
There is 3 tickets left because there is only 3 adults tickets left.
Answer:
The answer to your question is 1.875 gallons
Step-by-step explanation:
Data
distance = 50 mi
volume of gas = 1 gal
volume for 150 km = ?
Process
1.- Convert 50 mi into kilometers
1 mile ------------------- 1.6 km
x ------------------ 150 km
x = (150 x 1)/1.6
x = 93.75 mi
2.- Calculate the gallons wasted
1 gallon ----------------- 50 mi
x ---------------- 93.75 mi
x = (93.75 x 1)/50
x = 93.75/50
x = 1.875 gallons
First, find the total length of the line.
2 + 4 + 5 = 11
Second, find the length of LM.
LM = 4 units
Third, put the length of LM in a fraction with the total length.
4/11
Therefore, the answer is A.
Best of Luck!
