Let one integer be x, the consecutive odd integer is x+2
reciprocals are 1/x and 1/(x+2)
1/x +1/(x+2)=24/143
make the denominators the same:
(x+2)/[x(x+2)] +x/[x(x+2)]=24/143
143(2x+2)=24(x)(x+2)
286x+286=24x²+48x
24x²-238x-286=0
use the quadratic formula: x=22 this doesn't work because 22 is not an odd number.
or x=-2.1666666666 (this is not an integer)
weird.
First you need to see that this is a quadratic. I need.to put all of the values on one side of equation to see what I got.
6r^2 + 7r + 8 = 6
6r^2 + 7r + 2 = 0
Now this one is difficult to factor so i will use quadratic equation:
[-b (+-) sqrt (b^2 - 4ac)] / (2a)
we know that a b and c are in a quadratic at these positions.
ax^2 + bx + c
so
[-7 (+-) sqrt (7^2 -(4)(6)(2)] / (2) (6)
[-7 (+-) sqrt (49 - 48)] / 12
[-7 (+-) 1] /12
split into the + and - for 2 answers
(-7 + 1) / 12
-6/12
-1/2
And
(-7 -1) /12
-8 / 12
-2/3
those are.the 2 answers
But but it says largest so -1/2
Less than means to subtract so 2678 less than 10000 will be
=10000-2678
=7322
119/8 is already in simplest form. However, if you attempt to change it to a mixed number the correct answer would be 14 7/8 (7 over 8).
Hope I helped!
In this situation, 0.782 would be rounded to 0.8
how to round a decimal: take the underlined number and look to the number located to the RIGHT of the underlined number, if the number to the right of the underlined number is 4 or less you leave the underlined number as is - but if the number right to underlined number is 5 or greater you round the underlined number up by one
ex. 1.83 [round to the nearest tenth]
answer: 1.80
instead of keeping the 3 [hundredth] you turn it into a 0.
