No, 78 is the absolute value of 78. 78 is the absolute value of -78 too.
Answer:
y = 2x + 1 --> linear
y = -4x + 7 --> non-linear
Not a solution for linear system.
Step-by-step explanation:
for (a), y = 2x+1, substitute the x and y values. keep in mind, that in a linear pair, (x, y). So, for the first equation you get:
7 = 2x3 + 1. This is correct, because 6 + 1 is 7. Therefore, (a) is linear.
for (b), we have to substitute our values again. You get:
7 = -4x3 + 7, which is
7 = -12+7, which is not true. So, (b) is not linear.
This means that for the linear pair (3, 7), it does not satisfy both equations, which means that it is not a solution for the linear system.
<span>The perimeter of a Triangle is the sum of three sides ; ie assuming k,l,m be the three sides of a triangle means then k+l+m = perimeter of a triangle.
here given that a two sides lengths are 2x+ 2 and 5x-4 ;
and the perimeter length is 16x-6;
let the unknown side be k;
therefore k + 2x+2 + 5x-4 = 16x-6;
resolving k + 7x-2 = 16x-6;
Ans:-
k= 16x-6-7x+2 = 9x-4 ie the
unknown length k is 9x-4</span>
Let A = {−2, −1, 0, 1, 2, 3, 4, 5, 6} and define a relation R on A as follows: For all (m, n) is in A, m R n ⇔ 5|(m2 − n2). It i
anastassius [24]
Answer:
Step-by-step explanation:
find the attached answer below