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3 years ago

The area between z=0 and z=1 under the standard normal curve is ?

Mathematics

1 answer:

Alex17521 [72]3 years ago

7 0

According to the Empirical Rule, 68% of data lies within 1 std. dev. of the mean. Thus, between z=0 and z=1 lie half of that, or 34%, of the data.

Using a calculator for a more precise answer:

normalcdf(0,1) = 0.3413 (answer)

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I need to find the answer for "n" -(n - 8) = -2

astra-53 [7]

Answer:

n = 10

Step-by-step explanation:

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3 years ago

Eve measured a county park and made a scale drawing. The picnic area, which is 68 yards wide in real life, is 34 inches wide in

mote1985 [20]

Answer:

Eve used scale as 2 yards is equal to 1 inch.

Step-by-step explanation:

Given:

Actual Picnic area = 68 yards.

Drawing Picnic area = 34 inches.

We need to find the scale used by Eve.

Solution:

Now we can say that;

scale used by Eve can be calculated by dividing Actual Picnic area from drawing picnic area.

framing in equation form we get;

scale used by Eve = $\frac{68}{34} = 2\ yd/in$

Hence Eve used scale as 2 yards is equal to 1 inch.

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3 years ago

What is the measure of an exterior angle in a regular polygon with 15 sides?

vlabodo [156]

First, find the measure of an interior angle:
the sum of the interior angles of a polygon is (n-2)*180, n is the number of sides
for a 15-sided polygon, the sum is 13*180
each interior angle is then 13*180/15=156
the measure of each exterior angle=180-156=24

4 0

3 years ago

Read 2 more answers

While her husband spent 2½ hours picking out new speakers, a statistician decided to determine whether the percent of men who en

AVprozaik [17]

Answer:

$z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}$ (1)

$z=\frac{0.34848-0.34782}{\sqrt{0.34831(1-0.34831)(\frac{1}{66}+\frac{1}{23})}}=0.0057$

$p_v =P(Z>0.0057)=0.4977$

The p value is a very high value and using the significance level $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the percent of men who enjoy shopping for electronic equipment is NOT significantly higher than the percent of women who enjoy shopping for electronic equipment.

Step-by-step explanation:

1) Data given and notation

$X_{M}=23$ represent the number of men that said they enjoyed the activity of Saturday afternoon shopping

$X_{W}=8$ represent the number of women that said they enjoyed the activity of Saturday afternoon shopping

$n_{M}=66$ sample of male selected

$n_{W}=23$ sample of demale selected

$p_{M}=\frac{23}{66}=0.34848$ represent the proportion of men that said they enjoyed the activity of Saturday afternoon shopping

$p_{W}=\frac{8}{23}=0.34782$ represent the proportion of women with red/green color blindness

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to check if the percent of men who enjoy shopping for electronic equipment is higher than the percent of women who enjoy shopping for electronic equipment , the system of hypothesis would be:

Null hypothesis: $p_{M} \leq p_{W}$

Alternative hypothesis: $p_{M} > p_{W}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}$ (1)

Where $\hat p=\frac{X_{M}+X_{W}}{n_{M}+n_{W}}=\frac{23+8}{66+23}=0.34831$

3) Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.34848-0.34782}{\sqrt{0.34831(1-0.34831)(\frac{1}{66}+\frac{1}{23})}}=0.0057$

4) Statistical decision

Using the significance level provided $\alpha=0.05$ , the next step would be calculate the p value for this test.

Since is a one side right tail test the p value would be:

$p_v =P(Z>0.0057)=0.4977$

So the p value is a very high value and using the significance level $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the percent of men who enjoy shopping for electronic equipment is NOT significantly higher than the percent of women who enjoy shopping for electronic equipment.

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3 years ago

It would take 150 minutes to fill a swimming pool using the water from 5 taps.

mina [271]

Answer: points for points

Step-by-step explanation:

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3 years ago