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gogolik [260]
3 years ago
13

Find the slope of each line.A) -4/5B) 1C) -1 D) 4/5​

Mathematics
2 answers:
MAVERICK [17]3 years ago
7 0

Answer:

C) -1

Step-by-step explanation:

2--2= 4

-4-0= -4

Hope This Helps & Good Luck Bud

4/-4= -1

bagirrra123 [75]3 years ago
6 0

Answer:

C) - 1

Step-by-step explanation:

Line is passing through the points (-2, 0) & (0, - 2)

\therefore \: slope \: m =  \frac{ - 2 - 0}{0 - ( - 2)}  =  \frac{ - 2}{2}  =  - 1

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Which equation is related to..???
Trava [24]

Answer:

that is the solution to the question

8 0
3 years ago
1. A pond has 85 frogs, 20% of the frogs are green the rest are orange, brown, and yellow. How many frogs are green?​
alexandr402 [8]

Answer:

17 green frogs

Step-by-step explanation:

You need to multiply the decimal form of 20% by 85.

To find the decimal form of a percent you take the decimal (20.00) and move it twice to the left (20.00 ---> .2000)

Now, multiply by .2 by 85

(.2)(85) = 17

Therefore, 17 frogs in the pond of 85 frogs are green

<em>Hope this helps!!</em>

<em>- Kay :)</em>

4 0
3 years ago
Hi whats the answer<br> √548
harkovskaia [24]
23.409399821439250218
6 0
3 years ago
Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)
babunello [35]

\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k

We want to find f(x,y,z) such that \nabla f=\vec F. This means

\dfrac{\partial f}{\partial x}=x^2+y

\dfrac{\partial f}{\partial y}=y^2+x

\dfrac{\partial f}{\partial z}=ze^z

Integrating both sides of the latter equation with respect to z tells us

f(x,y,z)=e^z(z-1)+g(x,y)

and differentiating with respect to x gives

x^2+y=\dfrac{\partial g}{\partial x}

Integrating both sides with respect to x gives

g(x,y)=\dfrac{x^3}3+xy+h(y)

Then

f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+h(y)

and differentiating both sides with respect to y gives

y^2+x=x+\dfrac{\mathrm dh}{\mathrm dy}\implies\dfrac{\mathrm dh}{\mathrm dy}=y^2\implies h(y)=\dfrac{y^3}3+C

So the scalar potential function is

\boxed{f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+\dfrac{y^3}3+C}

By the fundamental theorem of calculus, the work done by \vec F along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it L) in part (a) is

\displaystyle\int_L\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(4,0,0)=\boxed{1+3e^4}

and \vec F does the same amount of work over both of the other paths.

In part (b), I don't know what is meant by "df/dt for F"...

In part (c), you're asked to find the work over the 2 parts (call them L_1 and L_2) of the given path. Using the fundamental theorem makes this trivial:

\displaystyle\int_{L_1}\vec F\cdot\mathrm d\vec r=f(0,0,0)-f(4,0,0)=-\frac{64}3

\displaystyle\int_{L_2}\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(0,0,0)=\frac{67}3+3e^4

8 0
3 years ago
Help me with these please
mixas84 [53]

Answer:

A) SAS

Step-by-step explanation:

The picture gives us that two sides are congruent. We can see that an <em>angle</em> is congruent as well because they share a common point at their tip.

If we look at just the area of intersection, it looks like an X. Think of the X as two lines intersecting. Each side equals 180°, and because both triangles are made up of those sides, we can conclude that the angles are congruent as well.

Hope this helps!

3 0
3 years ago
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