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3 years ago

Match these items.

Chemistry

2 answers:

lorasvet [3.4K]3 years ago

7 0

Explanation:

For 1: The correct answer is Option c.

$HC\equiv CH$ is an alkyne having triple bond between two carbon atoms.

For 2: The correct answer is Option g.

Benzene is a cyclic compound having 6 carbon atoms, where alternate carbon atoms are bonded with a double bond (or have unsaturation)

For 3: The correct answer is Option e.

The general formula to write any alkene (having double bond) is $C_nH_{2n}$ , where n = 1, 2, 3,4....

For 4: The correct answer is Option a.

Unsaturated hydrocarbons are the compounds having double and triple bond present between two carbon atoms. The common reaction which all unsaturated hydrocarbons undergo is addition reaction.

For 5: The correct answer is Option f.

The general formula to write any alkyne (having triple bond) is $C_nH_{2n-2}$ , where n = 1, 2, 3,4....

For 6: The correct answer is Option d.

The hydrocarbons where a triple bond is present between two carbon atoms belong to a group known as alkyne.

For 7: The correct answer is Option b.

The general formula to write any alkane (having single bond) is $C_nH_{2n+2}$ , where n = 1, 2, 3,4....

mars1129 [50]3 years ago

6 0

Here are the possible answers for the following questions above:
1. H-CC-H (name) - C. ethyne
2. cyclic compound with both saturated and unsaturated characteristics - G. benzene
3. CnH2n - E. general formula for alkenes
4. reaction typical of unsaturated hydrocarbons - A. addition
5. CnH2n-2 - F. general formula for alkynes
6. series name of hydrocarbons with triple bond - D. alkyne
7. CnH2n+2 - B. general formula of alkanes

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What is the mass of 1.58 moles of CH4

HACTEHA [7]

<h3>Answer:</h3>

25.4 g CH₄

<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Atomic Structure

Reading a Periodic Table

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<h3>Explanation:</h3>

Step 1: Define

1.58 mol CH₄

Step 2: Identify Conversions

[PT] Molar Mass of C - 12.01 g/mol

[PT] Molar Mass of H - 1.01 g/mol

Molar Mass of CH₄ - 12.01 + 4(1.01) = 16.05 g/mol

Step 3: Convert

Set up: $\displaystyle 1.58 \ mol \ CH_4(\frac{16.05 \ g \ CH_4}{1 \ mol \ CH_4})$
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3 years ago

g When aqueous solutions of and are mixed, a solid forms. Determine the mass of solid formed when 140.7 mL of 0.1000 M is mixed

solong [7]

The question is incomplete, the complete question is:

When aqueous solutions of NaCl and $Pb(NO_3)_2$ are mixed, a solid forms. Determine the mass of solid formed when 140.7 mL of 0.1000 M NaCl is mixed with an excess of an aqueous solution of

Answer: The mass of lead chloride produced is 1.96 g

Explanation:

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

$\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{ \text{Volume of solution (mL)}}$ .....(1)

Given values:

Molarity of NaCl = 0.1000 M

Volume of the solution = 140.7 mL

Putting values in equation 1, we get:

$0.1000=\frac{\text{Moles of NaCl}\times 1000}{140.7}\\\\\text{Moles of NaCl}=\frac{0.1000\times 140.7}{1000}=0.01407mol$

The chemical equation for the reaction of NaCl and lead nitrate follows:

$Pb(NO_3)_2(aq)+2NaCl(aq)\rightarrow PbCl_2(s)+2NaNO_3(aq)$

By the stoichiometry of the reaction:

If 2 moles of NaCl produces 1 mole of lead chloride

So, 0.01407 moles of NaCl will produce = $\frac{1}{2}\times 0.01407=0.007035mol$ of lead chloride

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(2)

Molar mass of lead chloride = 278.1 g/mol

Plugging values in equation 2:

$\text{Mass of lead chloride}=(0.007035mol\times 278.1g/mol)=1.96g$

Hence, the mass of lead chloride produced is 1.96 g

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3 years ago

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ss7ja [257]

Based on the calculations, the approximate ductility (%el) of this brass is equal to 2.3%.

Given the following data:

Yield strength = 230 mpa (33360 psi).

<h3>What is ductility?</h3>

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Mathematically, the ductility of a material can be expressed as percentage elongation in length:

$\% el = \frac{\Delta L}{L_i} =\frac{L_f - L_i}{L_i}$