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3 years ago

Match these items.

Chemistry

2 answers:

lorasvet [3.4K]3 years ago

7 0

Explanation:

For 1: The correct answer is Option c.

$HC\equiv CH$ is an alkyne having triple bond between two carbon atoms.

For 2: The correct answer is Option g.

Benzene is a cyclic compound having 6 carbon atoms, where alternate carbon atoms are bonded with a double bond (or have unsaturation)

For 3: The correct answer is Option e.

The general formula to write any alkene (having double bond) is $C_nH_{2n}$ , where n = 1, 2, 3,4....

For 4: The correct answer is Option a.

Unsaturated hydrocarbons are the compounds having double and triple bond present between two carbon atoms. The common reaction which all unsaturated hydrocarbons undergo is addition reaction.

For 5: The correct answer is Option f.

The general formula to write any alkyne (having triple bond) is $C_nH_{2n-2}$ , where n = 1, 2, 3,4....

For 6: The correct answer is Option d.

The hydrocarbons where a triple bond is present between two carbon atoms belong to a group known as alkyne.

For 7: The correct answer is Option b.

The general formula to write any alkane (having single bond) is $C_nH_{2n+2}$ , where n = 1, 2, 3,4....

mars1129 [50]3 years ago

6 0

Here are the possible answers for the following questions above:
1. H-CC-H (name) - C. ethyne
2. cyclic compound with both saturated and unsaturated characteristics - G. benzene
3. CnH2n - E. general formula for alkenes
4. reaction typical of unsaturated hydrocarbons - A. addition
5. CnH2n-2 - F. general formula for alkynes
6. series name of hydrocarbons with triple bond - D. alkyne
7. CnH2n+2 - B. general formula of alkanes

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Half-life is the time required for the amount of a sample to half its value.
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1. $(1/2)^{n} = x$ ,
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n - a number of half-lives
x - a remained fraction of a sample

2. $t_{1/2} = \frac{t}{n}$
where:
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t - total time elapsed
n - a number of half-lives

The half-life of Sr-90 is 28.8 years.
So, we know:
t = 87.3 years
 $t_{1/2}$ = 28.8 years

We need:
n = ?
x = ?

We could first use the second equation, to calculate n:
If:
$t_{1/2} = \frac{t}{n}$ ,
Then:
$n = \frac{t}{ t_{1/2} }$
⇒ $n = \frac{87.3 years}{28.8 years}$
⇒ $n=3.03$
⇒ n ≈ 3

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