The mass after 16.042 days : 1.4 g
<h3>Further explanation</h3>
Given
mass of 5.6 gram sample of I-131
time=16.042 days
Required
The mass of a sample
Solution
General formulas used in decay:
T = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
Half-life of I-131 = 8 days
Input the value :
The answer is (3), BaCl2 and N2O4. In this choice, BaCl2 is ionic compound and N2O4 is molecular compound. For others, NaOH and BaSO4 are ionic compounds. N2, SO2, Cl2, and H2S are molecular compounds.
Answer:
Molecular Formula = C₄O₂H₈
Explanation:
Molecular formula is calculated from following formula.
Molecular Formula = n(Empirical formula)
The formula for n is given as,
n = Molecular Formula Mass / Empirical Formula Mass
Molecular Formula mass = 88 g/mol
Empirical formula mass = 44
Putting values,
n = 88 / 44 = 2
Now,
Molecular Formula = 2(C₂OH₄)
Molecular Formula = C₄O₂H₈
THE ANSWERS ARE A AND B!!!!
HOPE I HELPED
Answer:
56.24g
Explanation:
To find the mass of N2O3 in 4.45 x 10^23 molecules, it must first be converted to moles by dividing the number of molecules in N2O3 by Avagadro's number (6.02 × 10^23).
number of moles in N2O3 = 4.45 x 10^23 ÷ 6.02 × 10^23
n = 4.45/6.02 × 10^(23 - 23)
n = 0.74 × 10^0
n = 0.74moles.
Using the formula below to find the mass of N2O3;
mole = mass ÷ molar mass
Molar mass of N2O3 = 14(2) + 16(3)
= 28 + 48
= 76g/mol
mass = mole × molar mass
Mass = 0.74 × 76
Mass = 56.24g
