Kinetic energy = 29.912 J
<h3>Further explanation</h3>
Given
mass = 0.155 kg
vo=initial velocity = 31.4 m/s
h/d=30 m
Required
KE=kinetic energy
Solution
vt²=vo²-2ad⇒vt=final velocity
vt²=31.4²-2.10.30⇒g=10 m/s²
vt²=985.96-600
vt²=385.96 m/s
Kinetic energy (KE)
<h2>
Answer:</h2>
6C
<h2>
Explanation:</h2>
The quantity of charge, Q, passing through an electric circuit is dependent on the electric current, I, and the time taken, t, for the current to flow. It is given mathematically as follows
Q = I x t ------------------------------(i)
Where;
I is measured in Amperes(A)
t is measured in seconds (s)
Q is measure in coulombs (C)
<em>From the question,</em>
I = 3A
t = 2s
<em>Substitute these values into equation (i) as follows;</em>
Q = 3 x 2
Q = 6C
Therefore, the number of coulombs of charge that will pass is 6C
Juan lives a hundred miles away from Bill then the average speed that he reaches Bill's Home in 50 seconds means that Juan lives 50 seconds away from bill because 50 + 50 seconds equals 100 seconds so Juansorry my bad Juan lives 50 miles away from Belle but he probably how I must have run to get to bill in 50 seconds .