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tiny-mole [99]
3 years ago
8

If the intensity level by 15 identical engines in a garage is 100 dB, what is the intensity level generated by each one of these

engines?
Physics
1 answer:
goblinko [34]3 years ago
8 0

To develop this problem we will apply the concepts related to Sound Intensity. This can be defined as the power carried by sound waves per unit area in a direction perpendicular to that area. Mathematically it can be written as,

\Delta L = 10log(n)

\Delta L = Level Difference

n = Number of equal loud sound sources

n = 15

Therefore replacing we have,

\Delta L = 10 log (n)\\\Delta L = 10 log (15)\\\Delta L = 10*1.176\\\Delta L = 11.76dB

Therefore over 100dB the total difference intensity level would be

L_T = L_0 -\Delta L

Here,

L_0 = \text{ Total intensity}

\L_T = 100 -11.76

_T= 88.24dB

The intensity level generated by one engine is

L_T = 88.44dB

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Complete Question

The  complete question is  shown on the first uploaded image  

Answer:

a

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b

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From the question we are told that

    The  image distance is  d_i =  -75 cm

The value of the image is negative because it is on the same side with the corrective glasses

    The  object distance is  d_o =  \infty

The  reason object distance  is because the object father than it being picture by the eye

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