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3 years ago

8

If the intensity level by 15 identical engines in a garage is 100 dB, what is the intensity level generated by each one of these

engines?

1 answer:

goblinko [34]3 years ago

8 0

To develop this problem we will apply the concepts related to Sound Intensity. This can be defined as the power carried by sound waves per unit area in a direction perpendicular to that area. Mathematically it can be written as,

$\Delta L = 10log(n)$

$\Delta L$ = Level Difference

n = Number of equal loud sound sources

n = 15

Therefore replacing we have,

$\Delta L = 10 log (n)\\\Delta L = 10 log (15)\\\Delta L = 10*1.176\\\Delta L = 11.76dB$

Therefore over 100dB the total difference intensity level would be

$L_T = L_0 -\Delta L$

Here,

$L_0 = \text{ Total intensity}$

$\L_T = 100 -11.76$

$_T= 88.24dB$

The intensity level generated by one engine is

$L_T = 88.44dB$

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3 years ago

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3 years ago

Read 2 more answers

A baseball is thrown at an angle of 25 degrees relative to the ground at a speed of 23 m/s. If the ball was caught 42 m from the

ExtremeBDS [4]

Answer:

a) $v_{0y} = 9.72 m/s$

b) $v_{0x} = 20.85 m/s$

c) $t = 2.01 s$

d) $h_{max} = 4.82 m$

Explanation:

a) The initial vertical velocity is given by:

$v_{0y} = v*sin(\theta)$

Where:

θ: 25°

v: is the magnitude of the speed = 23 m/s

$v_{0y} = 23 m/s*sin(25) = 9.72 m/s$

b) The initial horizontal velocity can be calculated as follows:

$v_{0x} = v*cos(\theta) = 23 m/s*cos(25) = 20.85 m/s$

c) The flight time can be calculated using the following equation:

$v_{0x} = \frac{x}{t}$

Where:

x: is the total distance = 42 m

$t = \frac{x}{v_{0x}} = \frac{42 m}{20.85 m/s} = 2.01 s$

d) The maximum height is given by:

$v_{fy}^{2} = v_{0y}^{2} - 2gh_{max}$

Where:

$v_{fy}$ : is the final vertical velocity =0 (at the maximum heigth)

g: is the gravity = 9.81 m/s²

$h_{max} = \frac{v_{0y}^{2}}{2g} = \frac{(9.72 m/s)^{2}}{2*9.81 m/s^{2}} = 4.82 m$

I hope it helps you!

7 0

3 years ago

during a crash, the acceleration was less than 30g. Calculate the force on a 70 kg person accelerating at this rate.

Igoryamba

Answer:

less than 20580 N

Explanation:

According to the newton's second law of motion

Force = mass * acceleration

(assuming gravitational acceleration =9.8 m/s2 )

acceleration = 30*9.8 = 294 m/s2

acting Force = 70 * 294

= 20580 N

Since the acceleration was less than 30g , acting force should also be less than 20580 N

4 0

3 years ago