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tiny-mole [99]
3 years ago
8

If the intensity level by 15 identical engines in a garage is 100 dB, what is the intensity level generated by each one of these

engines?
Physics
1 answer:
goblinko [34]3 years ago
8 0

To develop this problem we will apply the concepts related to Sound Intensity. This can be defined as the power carried by sound waves per unit area in a direction perpendicular to that area. Mathematically it can be written as,

\Delta L = 10log(n)

\Delta L = Level Difference

n = Number of equal loud sound sources

n = 15

Therefore replacing we have,

\Delta L = 10 log (n)\\\Delta L = 10 log (15)\\\Delta L = 10*1.176\\\Delta L = 11.76dB

Therefore over 100dB the total difference intensity level would be

L_T = L_0 -\Delta L

Here,

L_0 = \text{ Total intensity}

\L_T = 100 -11.76

_T= 88.24dB

The intensity level generated by one engine is

L_T = 88.44dB

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4 0
3 years ago
Initially a car accelerates at 2 m/s2 for x seconds. The car then travels at a velocity of -6 m/s for x seconds. If the car disp
Luda [366]

Answer:

The time travel is

t=8 s

Explanation:

a= 2 \frac{m}{s^{2} } \\v=-6 \frac{m}{s} \\x=16m

x_{f}=x_{o}+v_{o}*t+\frac{1}{2} *a*t^{2}

x_{f}=0-6*t+\frac{1}{2} *2*t^{2}

t^{2}-6*t-16=0\\ using :\\\frac{-b+/-\sqrt{b^{2}-4*c*a } }{2} \\\frac{-(-6)+/-\sqrt{(-6)^{2}-4*(-16)*(1) } }{2}=\frac{3}{2} +/- \frac{10}{2} \\t_{1} = 2s \\t_{2} = 8s

Check

t_{2}=8s

x_{f}=x_{o}+v_{o}*t+\frac{1}{2} *a*t^{2}

x_{f}=0-6*+\frac{1}{2} *2*8^{2}

x_{f}=-48+64\\x_{f}=16

5 0
3 years ago
The conservation laws, show ift<br>te-te​
FinnZ [79.3K]

Answer:

Explanation:

In physics, a conservation law states that a particular measurable property of an isolated physical system does not change as the system evolves over time. The exact conservation laws include conservation of energy, and conservation of linear momentum, and also conservation of angular momentum, aswell as the conservation of electric charge

7 0
3 years ago
using hooke's law, f spring = k triangle x, find the elastic constant of a spring that stretches 2 cm when a 4 newton force is a
Ksivusya [100]

As we know that spring force is given as

F = kx

here we know that

F = 4 N

x = 2 cm = 0.02 m

now from the above equation we will have

4 = k(0.02)

k = 200 N/m

so the elastic constant of the spring will be 200 N/m

8 0
3 years ago
A photon with an energy E = 2.12 GeV creates a proton-antiproton pair in which the proton has a kinetic energy of 96.0 MeV. What
Oksanka [162]

Answer:

The kinetic energy of the anti proton is 147.4 MeV.

Explanation:

Given that,

Energy = 2.12 GeV

Kinetic energy = 96.0 MeV

We need to calculate the kinetic energy of the anti proton

Using formula of energy

E_{photon}=m_{p}c^2+m_{np}c^2+K.E_{p}+K.E_{np}

We know that,

m_{p}c^2=m_{np}c^2

So, E_{photon}=2mc^2+K.E_{p}+K.E_{np}

K.E_{np}=E_{photon}-(2mc^2+K.E_{p})

Put the value into the formula

K.E_{np}=2.12\times10^{9}-2\times938.3\times10^{6}-96\times10^{6}

K.E_{np}=147.4\ MeV

Hence, The kinetic energy of the anti proton is 147.4 MeV.

6 0
3 years ago
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