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3 years ago

How does SCOTUS view information obtained by private citizens and subsequently shared with law enforcement?

Physics

1 answer:

scoundrel [369]3 years ago

5 0

Answer:

as a legal search

Explanation:

In the specific case, there was a trespass on private property through the installation of a global positioning system (GPS) to gather sensitive information about the citizen. This is considered a legal search and is not appropriate to conduct such an investigation without proper approval from the relevant authority.

You might be interested in

Which of two factors influence the weight of an object due to gravitational pull?

densk [106]

The weight of an object when calculated by multiplying with the pull of the gravity is dependent on the mass of the object and the value of g. The value of g is constant however is still dependent on the distance of the object from the center of the Earth. Thus, the answers are <em>mass and distance. </em>

5 0

3 years ago

Which of the following provides evidence that Earth's Moon is rotating and revolving at the same rate?

kkurt [141]

B. We can see only one side of the Moon from Earth.

( we only see one side of the moon because the moon rotates around the Earth)

6 0

2 years ago

A space probe is fired as a projectile from the Earth's surface with an initial speed of 2.05 104 m/s. What will its speed be wh

Elanso [62]

Answer:

The value is $v = 2.3359 *10^{4} \ m/s$

Explanation:

From the question we are told that

The initial speed is $u = 2.05 *10^{4} \ m/s$

Generally the total energy possessed by the space probe when on earth is mathematically represented as

$T__{E}} = KE__{i}} + KE__{e}}$

Here $KE_i$ is the kinetic energy of the space probe due to its initial speed which is mathematically represented as

$KE_i = \frac{1}{2} * m * u^2$

=> $KE_i = \frac{1}{2} * m * (2.05 *10^{4})^2$

=> $KE_i = 2.101 *10^{8} \ \ m \ \ J$

And $KE_e$ is the kinetic energy that the space probe requires to escape the Earth's gravitational pull , this is mathematically represented as

$KE_e = \frac{1}{2} * m * v_e^2$

Here $v_e$ is the escape velocity from earth which has a value $v_e = 11.2 *10^{3} \ m/s$

=> $KE_e = \frac{1}{2} * m * (11.3 *10^{3})^2$

=> $KE_e = 6.272 *10^{7} \ \ m \ \ J$

Generally given that at a position that is very far from the earth that the is Zero, the kinetic energy at that position is mathematically represented as

$KE_p = \frac{1}{2} * m * v^2$

Generally from the law energy conservation we have that

$T__{E}} = KE_p$

$2.101 *10^{8} m + 6.272 *10^{7} m = \frac{1}{2} * m * v^2$

=> $5.4564 *10^{8} = v^2$

=> $v = \sqrt{5.4564 *10^{8}}$

=> $v = 2.3359 *10^{4} \ m/s$

4 0

2 years ago

Two cannonballs are dropped from a second-floor physics lab at height h above the ground. Ball B has four times the mass of ball

denpristay [2]

Answer:

1:4

Explanation:

The formula for calculating kinetic energy is:

$KE=\dfrac{1}{2}mv^2$

If the mass is multiplied by 4, then, the kinetic energy must be increased by 4 as well. Since they will be travelling at the same speed when they are at the same point, the relation between KA and KB must be 1:4 or 1/4. Hope this helps!

3 0

2 years ago

A magnet has ___________ poles. Like poles__________each other and unlike poles __________. An electromagnet is used to separate

Stels [109]

Answer:

2 repel attracts light water

3 0

2 years ago

Read 2 more answers