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qaws [65]
3 years ago
8

Heating causes an object to dxpena

Physics
1 answer:
JulsSmile [24]3 years ago
4 0
The Answer Would You Are Looking For Would Be:
~Expand.

Hope this helps.
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If then hypothesis for egg drop
Marina86 [1]
If I drop my egg unprotected, then it will break.
6 0
3 years ago
20 POINTS! TRUE OR FALSE:
Vladimir79 [104]

Answer: TRUE

Explanation:

5 0
3 years ago
A Ferris wheel with radius 14.0 m is turning about a horizontal axis through its center. The linear speed of a passenger on the
Marina86 [1]

Answer:

a) The acceleration experimented by the passenger when she passes through the lowest point of her circular motion is: a_{R} = 2.571\,\frac{m}{s^{2}}, \angle = 90^{\circ}.

b) Hence, the acceleration experimented by the passenger when she passes through the highest point of her circular motion is: a_{R} = 2.571\,\frac{m}{s^{2}}, \angle = 270^{\circ}.

c) The Ferris wheel takes 14.646 seconds to make a revolution.

Explanation:

a) An object that rotates at constant angular velocity reports a centripetal acceleration and no tangential acceleration. When passenger passes through the lowest point in her circular motion, centripetal acceleration goes up to the center.

In addition, centripetal acceleration is determined by the following expression:

a_{R} = \frac{v^{2}}{R} (Eq. 1)

Where:

a_{R} - Centripetal acceleration, measured in meters per square second.

v - Linear speed, measured in meters per second.

R - Radius of the Ferris wheel, measured in meters.

If we know that v = 6\,\frac{m}{s} and R = 14\,m, the magnitude of radial acceleration is:

a_{R} = \frac{\left(6\,\frac{m}{s} \right)^{2}}{14\,m}

a_{R} = 2.571\,\frac{m}{s^{2}}

The acceleration experimented by the passenger when she passes through the lowest point of her circular motion is: a_{R} = 2.571\,\frac{m}{s^{2}}, \angle = 90^{\circ}.

b) In the highest point the magnitude of radial acceleration is the same but direction is the opposed to that at lowest point. That is, centripetal acceleration goes down to the center.

Hence, the acceleration experimented by the passenger when she passes through the highest point of her circular motion is: a_{R} = 2.571\,\frac{m}{s^{2}}, \angle = 270^{\circ}.

c) At first we need to calculate the angular velocity of the Ferris wheel (\omega), measured in radians per second, by using the following expression:

\omega = \frac{v}{R} (Eq. 2)

If we know that v = 6\,\frac{m}{s} and R = 14\,m, then the angular velocity of the Ferris wheel is:

\omega = \frac{6\,\frac{m}{s} }{14\,m}

\omega = 0.429\,\frac{rad}{s}

Now we proceed to obtain the period of the Ferris wheel (T), measured in seconds, which is the time needed by that wheel to make on revolution:

T = \frac{2\pi}{\omega} (Eq. 3)

Where \omega is the angular velocity of the Ferris wheel, measured in radians per second.

If we get that \omega = 0.429\,\frac{rad}{s}, then:

T = \frac{2\pi}{0.429\,\frac{rad}{s} }

T = 14.646\,s

The Ferris wheel takes 14.646 seconds to make a revolution.

8 0
3 years ago
20 POINTS!!!
bogdanovich [222]

a) Average velocity for her run north: 2.68 m/s north

b) The average velocity for the whole trip is zero

c) The average speed for the whole trip is 1.95 m/s

Explanation:

a)

In this part of the problem we only want to consider the part when Micha is running north.

The average velocity is given by:

v=\frac{d}{t}

where

d is the displacement (a vector connecting the initial position to the final position of motion)

t is the time

For the part running north, we have

d=2 mil \cdot 1609 = 3218 m north is the displacement

t = 20 min \cdot 60 = 1200 s is the time interval

Substituting,

v=\frac{3218}{1200}=2.68 m/s north (we have to specify also the direction, since velocity is a vector)

b)

As we said, average velocity is given by

v=\frac{d}{t}

where

d is the displacement

t is the time

If we consider the whole trip, however, the displacement is zero:

d = 0

Because Micha returns home, so the initial position corresponds to the final position of motion. Therefore, the average velocity is also zero:

v = 0

c)

The average speed is given by

s=\frac{d}{t}

where

d is the  distance covered (the total length of the path, regardless of the direction)

t is the time interval

Since MIcha ran 2 miles north and then 2 miles back, the total distance is

d=2 mi + 2mi = 4 mi \cdot 1609 = 6436 m

And the time taken is

t=20 min + 15 min + 20 min = 55 min \cdot 60 = 3300 s

So, the average speed is

s=\frac{6436}{3300}=1.95 m/s

And since speed is a scalar, there is no need to specify a direction.

Learn more about speed and velocity:

brainly.com/question/8893949

brainly.com/question/5063905

brainly.com/question/5248528

#LearnwithBrainly

5 0
3 years ago
How long must a pendulum be to have a period of 4.6 5 on Neptune, where g = 11.15 m/s?​
Anon25 [30]

Answer:

5.98 m

Explanation:

T=2\pi \sqrt\frac{L}{g}

T^2=4\pi ^2L/g\\L = gT^2/(4\pi^2) = 11.15*4.6²/(4π²) = 5.98 m

5 0
2 years ago
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