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qaws [65]
2 years ago
8

Heating causes an object to dxpena

Physics
1 answer:
JulsSmile [24]2 years ago
4 0
The Answer Would You Are Looking For Would Be:
~Expand.

Hope this helps.
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Answer please I need help
madam [21]

Answer:

1) F

2) A

3) B

4) E

5) C

6) D

6 0
3 years ago
2. A 75 kg runner accelerates from 0.00 m/s to 10.0 m/s in 1.5 seconds.
raketka [301]
A :-) A.a.) Given - u = 0.00 m/s
v = 10.0 m/s
t = 1.5 sec
m = 75 kg
Solution -
a = v - u by t
a = 10 - 0 by 1.5
a = 10 by 1.5
a = 6.6 m/s^2

A.b.) sorry ! I don’t no how to do this question
3 0
3 years ago
What determines the state of matter for any
noname [10]

Answer:

I think the answer is B. amount of energy present but I'm not 100% sure

Explanation:

7 0
2 years ago
Read 2 more answers
Calculate the average drift speed of electrons traveling through a copper wire with a crosssectional area of 80 mm2 when carryin
Vedmedyk [2.9K]

Answer:

The correct answer is 2.8*10^{-5}ms^{-1}

Explanation:

The formula for the electron drift speed is given as follows,

u=I/nAq

where n is the number of of electrons per unit m³, q is the charge on an electron and A is the cross-sectional area of the copper wire and I is the current. We see that we already have A , q and I. The only thing left to calculate is the electron density n that is the number of electrons per unit volume.

Using the information provided in the question we can see that the number of moles of copper atoms in a cm³ of volume of the conductor is 8.93/63.5 molcm^{-3}. Converting this number to m³ using very elementary unit conversion we get 140384molm^{-3}. If we multiply this number by the Avagardo number which is the number of atoms per mol of any gas , we get the number of atoms per m³ which in this case is equal to the number of electron per m³ because one electron per atom of copper contribute to the current. So we get,

n=140384*6.02*10^{23} = 8.45*10^{28}electrons.m^{-3}

if we convert the area from mm³ to m³ we get A=80*10^{-6}m^{2}.So now that we have n, we plug in all the values of A ,I ,q and n into the main equation to obtain,

u=30/(8.45*10^{28}*80*10^{-6}*1.602*10^{-19})\\u=2.8*10^{-5}m.s^{-1}

which is our final answer.

6 0
3 years ago
A bird flies directly into the windshield of a moving car. How does the FORCE exerted on the car compare to the FORCE exerted on
Anarel [89]

Answer:

b

Explanation:

7 0
3 years ago
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