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kvasek [131]
3 years ago
13

How do you calculate the mean, medium, and range of the data in a dot plot?

Mathematics
1 answer:
adelina 88 [10]3 years ago
8 0
Add all numbers and divide the total by how many numbers there are
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What is the mean of all three-digit positive integers whose digits are in the set 2, 0, 1, 9.
salantis [7]
The mean for these digits are 3
4 0
3 years ago
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Find the value of x<br> 48°<br> 132°<br> 132°<br> X°
enot [183]

Answer:

X°

Step-by-step explanation:

there’s no other clues to what it could be, and since it’s x it would be X°

5 0
3 years ago
A random sample of 36 students at a community college showed an average age of 25 years. Assume the ages of all students at the
Pavel [41]

Answer:

98% confidence interval for the average age of all students is [24.302 , 25.698]

Step-by-step explanation:

We are given that a random sample of 36 students at a community college showed an average age of 25 years.

Also, assuming that the ages of all students at the college are normally distributed with a standard deviation of 1.8 years.

So, the pivotal quantity for 98% confidence interval for the average age is given by;

             P.Q. = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = sample average age = 25 years

            \sigma = population standard deviation = 1.8 years

            n = sample of students = 36

            \mu = population average age

So, 98% confidence interval for the average age, \mu is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98

P(-2.3263 < \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < 2.3263) = 0.98

P( -2.3263 \times {\frac{\sigma}{\sqrt{n} } < {\bar X - \mu} < 2.3263 \times {\frac{\sigma}{\sqrt{n} } ) = 0.98

P( \bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} } < \mu < \bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} } ) = 0.98

98% confidence interval for \mu = [ \bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} } , \bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} } ]

                                                  = [ 25 - 2.3263 \times {\frac{1.8}{\sqrt{36} } , 25 + 2.3263 \times {\frac{1.8}{\sqrt{36} } ]

                                                  = [24.302 , 25.698]

Therefore, 98% confidence interval for the average age of all students at this college is [24.302 , 25.698].

8 0
3 years ago
At a restaurant grand opening, a giant sandwich that was 352 centimeters long was divided equally among 22 people. Clyde got one
snow_lady [41]

Answer:

8 cm

Step-by-step explanation:

You neglected to include any equations

Here is one way to solve:

length of each piece

352/22 = 16

Half a piece

16/2 = 8

Choice C

352/22/2 = l

5 0
3 years ago
Marcus needs to rewrite f(x) = x2 + 6x + 4 in vertex form.
irakobra [83]

Hm, it seems like his answer is off. The image is what I got.

4 0
3 years ago
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