P² - r²
subtitute p =10 and r= -4
10² - (-4)² = 100 - 16 = 84
Answer: Most likely 13cm
Step-by-step explanation: <em>because it’s between 10cm and 16cm and thes no picture and set of choices so I hope this right.</em>
Answer:
<em>f(0)>f(1) and f(1)<f(2), therefore a critical point exists at f(1). As the value is greater before the critical point and is greater after as well, thus there exists a local minima at x=1.</em>
<em>f(3) <f(4) and f(4)>f(5), therefore a critical point exists at f(4). As the value is less before the critical point and is less after as well, thus there exists a local maxima at x=4.</em>
Step-by-step explanation:
As the data table is missing in the question, a similar question is found, which is as attached here with.
From the data of table
x | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
----------------------------------------------------
y=f(x) | -3 | -5 | -4 | -1 | 2 | 1 | -1 | -3 | -4 | -6 | -7 |
From the graph attached the critical points are as given below
As
<em>f(0)>f(1) and f(1)<f(2), therefore a critical point exists at f(1). As the value is greater before the critical point and is greater after as well, thus there exists a local minima at x=1.</em>
<em>f(3) <f(4) and f(4)>f(5), therefore a critical point exists at f(4). As the value is less before the critical point and is less after as well, thus there exists a local maxima at x=4.</em>
12/16 = 6/8 = 3/4
(there are 16 ounces in a pound)
H and J are out bc that's subtracting the 14 candy bars, which we just want to subtract the weight of the 10 oz of the box from 80 oz to get the total amount of candy bar ox, which equals 70 oz. Since you want to find how much each candy bar weighs you have to divide the difference between 14. - The answer is answer letter G.