Question

| Linus has 100 ft of fencing to

Answer 1

Answer:

$20 ft\times 60 ft$ or $30ft\times 40ft$

Step-by-step explanation:

We are given that

Total fencing used=100 ft

Area enclosed=1200 square ft

Let length of rectangular pig pen=x

Breadth of rectangular pig pen=y

Fencing used=2x+y

$100=2x+y$

$y=100-2x$

Area of rectangular pig pen=$xy=x(100-2x)$

$1200=100x-2x^2$

$2x^2-100x+1200=0$

$x^2-50x+600=0$

$x^2-20x-30x+600=0$

$x(x-20)-30(x-20)=0$

$(x-20)(x-30)=0$

$x=20$

$x-30=0\implies x=30$

When x=20ft

$y=100-2(20)=60$ft

When x=30 ft

$y=100-2(30)=40$ft

Dimension of fence is give  by

$20 ft\times 60 ft$ or $30ft\times 40ft$