Question

What is the equation of the line that passes through the point (-6,-2)and has a slope of 1/6

Answer 1

Answer:

y = 1/6x -1

Step-by-step explanation:

Use point-slope form: y - y₁ = m (x - x₁)

y - (-2) = 1/6 (x - (-6))

y + 2 = 1/6x + 1

y = 1/6x - 1

Answer 2

Answer:

$y=\frac{1}{6}x-1$

Step-by-step explanation:

According to,

y = mx + c

They have already given the slope of the line.

That means they've given value for m

So,

m = $\frac{1}{6}$

And now we have to find the value of c ( the intercept on the y axis) using (-6,-2)

Here,

 ( -6 , -2 )

   ↑    ↑

  ( x ,  y )

Let us find the c now.

y = mx + c

$-2 =\frac{1}{6} *-6+c\\-2=\frac{-6}{6} +c\\-2=-1+c\\-2+1=c\\-1=c$

Now let's write the equation of the line like this

y = mx+ c

$y=\frac{1}{6}x-1$

Hope this helps you.

Let me know if you have any other questions :-)