Answer:
<h2>By angle sum property:</h2>
BAC+ABC+BCA=180°
90°+45°+x=180°
135°+x=180°
x=45°=BCA
<h2>since BCA=ABC=<u> </u>45° each </h2><h2>therefore,</h2>
<h2><em><u>Hope </u></em><em><u>it </u></em><em><u>helps</u></em><em><u> you</u></em><em><u><</u></em><em><u>3</u></em></h2>
Answer:
(1/2,4)
Step-by-step explanation:
First, determine y in first equation: 2x+y=5 or y=5-2x
replace value of y determined in first equation (5-2x) into 2nd equation
4x-3(5-2x)=-10
4x-15+6x=10
10x=5
x=1/2
put value of x into either equation to solve for y so
2(1/2)+y=5
1+y=5
y=4
answer: x=1/2, y=4
check answer by substituting x and y into either equation:
4x-3y=-10
4(1/2)-3(4)=-10
2-12=-10
-10=-10
or
2x+y=5
2(1/2)+4=5
1+4=5
5=5
Answer: Assuming the a2 is a with an exponent of 2 and a3 is a with an exponent of 3, the answer is 2a^6-2a^5
Step-by-step explanation: the number after the ^ means to the power of
<span>150 degrees.
Let's assume the center camera is pointed to at an angle of 0 degrees. Since it has a coverage of 60 degrees, then it will cover the angles from -30 to +30 degrees. Now we'll continue to use the +/- 30 degree coverage for the other two cameras. The second camera is aimed at 45 degrees, so it's range of coverage is 15 degrees to 75 degrees (45 +/- 30). Notice that the range from 15 degrees to 30 degrees is covered by 2 cameras. Now the 3rd camera is pointed at -45 degrees, so its coverage is from -15 degrees to -75 degrees. It also has an overlap with the 1st camera from -15 to -30 degrees.
The total coverage of all three cameras ranges from -75 degrees to 75 degrees. That means that an arc of 150 degrees in total is covered by all three cameras.</span>
Answer:
24
Step-by-step explanation:
