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TEA [102]
3 years ago
14

Line segment XY has endpoints X(5, 7) and Y(– 3, 3). Find the equation for the perpendicular bisector of line segment XY.

Mathematics
1 answer:
Veronika [31]3 years ago
6 0

Answer:b

Step-by-step explanation:

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What’s the answer for the photo
Otrada [13]
Be nice if we were sure of the question. I will guess that you want the hypotenuse.

c^2 = a^2 + b^2
a = 6 km
b = 6 km

c^2 = 36 + 36
c^2 = 72
c = sqrt(72)
c = sqrt(9 * 8)
c = 3*sqrt(8)
c = 3 * 2.83
c = 8.49
7 0
3 years ago
What is surface area of cube if the only number is 5
Makovka662 [10]
Answer - 150
One square has an area of 25 (5x5) so 6 squares (25x6) have an area of 150.
8 0
3 years ago
Read 2 more answers
How to solve these two problems ?
puteri [66]

8)  \theta is -0.896 radians

9) length of arc is 41.91 cm

Solution:

8)

Given that,

tan\ \theta = \frac{-5}{4}

\theta is in quadrant 4

To find: \theta

From given,

tan\ \theta = \frac{-5}{4}\\\\\theta = tan^{-1} \frac{-5}{4}\\\\\theta = tan^{-1} (-1.25)\\\\\theta = -51.34

Thus value of \theta is -51.34 degrees

Convert degrees to radians

-51.34\ degree = -51.34 \times \frac{ \pi }{180}\ radian\\\\-51.34\ degree = -0.896\ radian

Thus \theta is -0.896 radians

9)

From given,

radius = 15.4 cm

\theta = \frac{13 \pi }{15}

<em><u>The length of arc when angle in radians is:</u></em>

arc\ length = r \times \theta\\\\arc\ length = 15.4 \times \frac{ 13 \pi }{15}\\\\arc\ length = 15.4 \times 2.721\\\\arc\ length = 41.91

Thus length of arc is 41.91 cm

4 0
3 years ago
A rectangular pool is 30 1/3 feet long and 12 1/2 feet wide. What is the area of the pool?
Tomtit [17]
<span>You just need to multiply them together the. You'll get 2275/6 or 379 1/6 sq feet</span>
4 0
2 years ago
C= 2 7r; for r<br> Plzz help
Nutka1998 [239]

Answer:

C/27=r

Step-by-step explanation:

C= 2 7r

C \div 27= 2 7r \div 27

C/27=r

5 0
3 years ago
Read 2 more answers
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