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TEA [102]
3 years ago
14

Line segment XY has endpoints X(5, 7) and Y(– 3, 3). Find the equation for the perpendicular bisector of line segment XY.

Mathematics
1 answer:
Veronika [31]3 years ago
6 0

Answer:b

Step-by-step explanation:

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In the graph below, Point A represents Owen's house, Point B represents David's house and Point C represents the school. Who liv
ycow [4]

Answer:

• David

,

• 4 miles

Explanation:

In the graph:

The given locations are:

• Owen's House, A(11,3)

,

• David's House, B(15,13)

,

• School, C(3,18)

We determine both Owen's and David's distance from the school using the distance formula.

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Owen's distance from school (AC)

\begin{gathered} AC=\sqrt[]{(3-11)^2+(18-3)^2} \\ =\sqrt[]{(-8)^2+(15)^2} \\ =\sqrt[]{64+225} \\ =\sqrt[]{289} \\ AC=17\text{ miles} \end{gathered}

David's distance from school (BC)

\begin{gathered} BC=\sqrt[]{(3-15)^2+(18-13)^2} \\ =\sqrt[]{(-12)^2+(5)^2} \\ =\sqrt[]{144+25} \\ =\sqrt[]{169} \\ BC=13\text{ miles} \end{gathered}

We see from the calculations that David lives closer to the school, and by 4 miles.

The graph below is attached for further understanding:

5 0
11 months ago
Input is also called? <br>Dependent Variable<br>Independent Variable​
irga5000 [103]

independent variable input

6 0
2 years ago
Read 2 more answers
PLZZ Help me algebra 2.
Kipish [7]

Answer:

32

Step-by-step explanation:

7 0
2 years ago
What is equivalent too 48j +36
Nata [24]
84j is the equivalent.
Just add 36 to 48 and put the j on.
7 0
2 years ago
Write the equation of a line that is parallel to y = 7x +13 that passes through the point (28, 8).
navik [9.2K]

Answer:

y=7x-188

Step-by-step explanation:

We know that this line must have a slope of 7, because this line is parallel to y=7x+13

We must use the point slope formula: y-y_{1}= m(x-x_{1})

Next, we will plug in the point (28,8) for y_{1} and x_{1}, and 7 in for m

y-8=7(x-28)

Solve the equation, first by distributing the 7

y-8=7x-196

Add the 8 over

y=7x-188

7 0
3 years ago
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