All categories

3 years ago

How to simplify bracket five x squared plus three x minus two bracket plus bracket three x minus two x plus five bracket

Mathematics

2 answers:

gizmo_the_mogwai [7]3 years ago

7 0

Answer:

5x²+4x+3

Step-by-step explanation:

I think, first you start with simplifying no. in the bracket in both sides then remove the bracket work with the remained according to their operation

Scilla [17]3 years ago

6 0

Answer:

5x^2 + 4x + 3.

Step-by-step explanation:

While I'm a little confused on what is closed and open parenthesis/brackets, I think I understand what you mean. In (5x^2+3x-2)+(3x-2x+5), the brackets can simply be removed as there is no multiplication between them. This means we get 5x^2 + 3x - 2 + 3x - 2x + 5. Combining like variables, we get 5x^2 + 4x + 3.

You might be interested in

What is the slope of the line that passes through the points (-3, 5) and (1, 7)?

Stells [14]

Answer: The slope of the line is $\frac{1}{2}$

Step-by-step explanation:

The slope of a line can be calculated with the following formula:

$m=\frac{y_2-y_1}{x_2-x_1}$

Then, given the points $(-3, 5)$ and $(1, 7)$ , you can identify that:

$y_2=5\\y_1=7\\\\x_2=-3\\x_1=1$

Knowing these values you can substitute them into the formula for calculate the slope:

$m=\frac{5-7}{-3-1}$

Finally, evaluating, you get that the slope of that line is:

$m=\frac{-2}{-4}\\\\m=\frac{1}{2}$

8 0

3 years ago

Simone told you that she placed a point on the number line that had an absolute value of 15. At what two numbers could she have

makvit [3.9K]

I positive 15 and negative 15, in effect the absolute value function just removed negative signs

6 0

3 years ago

Use the following figure to answer the question.

Mkey [24]

Answer:

corresponding

Step-by-step explanation:

because they are in the same place on both intersections. now if u ask me doggo deserve breinliest pwease ;-;

4 0

2 years ago

Read 2 more answers

Solve 2cos^2x + cosx − 1 = 0 for x over the interval [0, 2 π ).

alina1380 [7]

Let cos x = a, then
2a^2 + a - 1 = 0,
solving the quadratic equation, we have:
a = 0.5 or -1.

i.e. cos x = 0.5 or cos x = -1
for cos x = 0.5,
x = pi/3, 2pi - pi/3 = pi/3, 5pi/3

for cos x = -1,
x = pi

therefore, x = pi, pi/3, 5pi/3
Answer: B

6 0

3 years ago

What is the average rate of change of f over the interval -1 on a separate sheet of paper and upload the work as a photo. Show a

Anarel [89]

Answer:

Average rate of change for the function $f(x)= x^2-x-1$ over the interval -1<x<1 is -1

Step-by-step explanation:

We need to find average rate of change of f over the interval -1 < x < 1

The function given is: $f(x)= x^2-x-1$

The formula used to find average rate of change is:

$Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}$

We have, a = -1 and b = 1

Finding f(b) when b=1

$f(x)=x^2-x-1\\f(1)=(1)^2-(1)-1\\f(1)=1-1-1\\f(1)=-1$

Now, finding f(a), when a= -1

$f(x)=x^2-x-1\\f(-1)=(-1)^2-(-1)-1\\f(1)=1+1-1\\f(-1)=2-1\\f(-1)=1$

Now, putting values and finding average rate of change

$Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}\\Average\:rate\:of\:change=\frac{f(1)-f(-1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-(1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-1}{1+1}\\Average\:rate\:of\:change=\frac{-2}{2}\\Average\:rate\:of\:change=-1$

So, average rate of change for the function $f(x)= x^2-x-1$ over the interval -1<x<1 is -1

4 0

3 years ago