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hodyreva [135]
2 years ago
15

How to simplify bracket five x squared plus three x minus two bracket plus bracket three x minus two x plus five bracket

Mathematics
2 answers:
gizmo_the_mogwai [7]2 years ago
7 0

Answer:

5x²+4x+3

Step-by-step explanation:

I think, first you start with simplifying no. in the bracket in both sides then remove the bracket work with the remained according to their operation

Scilla [17]2 years ago
6 0

Answer:

5x^2 + 4x + 3.

Step-by-step explanation:

While I'm a little confused on what is closed and open parenthesis/brackets, I think I understand what you mean. In (5x^2+3x-2)+(3x-2x+5), the brackets can simply be removed as there is no multiplication between them. This means we get 5x^2 + 3x - 2 + 3x - 2x + 5. Combining like variables, we get 5x^2 + 4x + 3.

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Answer:

yes

Step-by-step explanation:

LMN should be a right triangle

use pythagorean theorem

18^2+80^2=82^2

it is a right triangle

7 0
2 years ago
What is another name for 23 ten thousands?
kicyunya [14]
<span>230,000

</span>Hope I Helped You!!! :-)

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2 years ago
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For the parallelogram ABCD the extensions of the angle bisectors AG and BH intersect at point P. Find the area of the parallelog
natita [175]

Answer:

The area of a parallelogram is 360 in.²

Step-by-step explanation:

Where DG = GH

GP = 12 in.

AB = 39 in.

∠DAB + ∠ABC = 180° (Adjacent angles of a parallelogram)

Whereby ∠DAB is bisected by AG and ∠ABC is bisected by BH

Therefore, ∠GAB + ∠HBA = 90°

Hence, ∠BPA = 90° (Sum of interior angles of a triangle)

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{AP}{39} = \dfrac{GP}{GH} =\dfrac{12}{GH}

We note that ∠AGD = ∠GAB (Alternate angles of parallel lines)

∴ ∠AGD = ∠AGD since ∠AGD = ∠GAB (Bisected angle)

Hence AD = DG (Side length of isosceles triangle)

The bisector of ∠ADG is parallel to BH and will bisect AG at point Q

Hence ΔDAQ  ≅ ΔDGQ ≅ ΔGPH and AQ = QG = GP

Hence, AP = 3 × GP = 3 × 12 = 36

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{36}{39}

\angle GAB = cos^{-1} \left (\dfrac{36}{39}  \right )

∠GAB = 22.62°

cos(\angle GAB) =  \dfrac{36}{39} = \dfrac{12}{GH}

GH =  \dfrac{39}{36} \times {12}

GH = 13 in.

∴ AD 13 in.

BP = 39 × sin(22.62°) = 15 in.

GH = √(GP² + HP²)

∠DAB = 2 × 22.62° = 45.24°

The height of the parallelogram = AD × sin(∠DAB) =  13 × sin(45.24°)

The height of the parallelogram = 120/13 =  9.23 in.

The area of a parallelogram = Base × Height = (120/13) × 39 = 360 in.²

7 0
3 years ago
Read 2 more answers
If the area of a circle is 58 square feet, find the circumference
Blizzard [7]

Answer:

C≈27 feet

Step-by-step explanation:

A=πr²

A/π=r²

√A/π =r or –√A/π=r (refused)

then r =√(A/π) =√(58/π) =4.297829403 feet

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7 0
3 years ago
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Write the number 2000000 in scientific notation​
konstantin123 [22]

Answer:

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Step-by-step explanation:

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3 years ago
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