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tankabanditka [31]
3 years ago
10

Pls help. Find the surface area of the solid. Round to the nearest tenth if necessary

Mathematics
1 answer:
Paladinen [302]3 years ago
8 0

Answer:

850 m²

Step-by-step explanation:

There are 3 different pairs of rectangles—the side rectangles, the rectangles on the top and bottom, and the other side rectangles.

10x11=110

110x2=220

15x10=150

150x2=300

15x11=165

165x2=330

330+300+220=850 m².

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Find AB when given angle B 64 degress angle C 75 degrese and side a 19
jeka94

Answer:

about 28

Step-by-step explanation:

you have to use the sine rule = side you know * ( sin of angle opposing the side you want to know / sin of angle opposing the side you know)

AB = 19* (sin 75/ sin ( 180 -75-64) )

AB = 19 * ( sin 75 / sin 41) ≈ 27.9739...

4 0
3 years ago
You randomly choose one of the tiles. Without replacing the first tile, you randomly choose a second tile. Find the probability
Lesechka [4]

Answer:

4/21

Step-by-step explanation:

I got the first probability and the second probabilty then multiplied them together.

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3 years ago
Compute $\sqrt{2\cdot 6^5 + 2\cdot 6^5 + 2\cdot 6^5}.$
jarptica [38.1K]

Answer:

216

Step-by-step explanation:

1. √{6^6}

2. √(6^3)^2}

3.6^3

4.216

Mark me Brainliest!

Hope this helps!

-ShadyK

7 0
3 years ago
How do you solve 9| x+8 | + 10 < 55 & how is it graphed
mafiozo [28]
Hello!

First, let's write the problem.
9\left|x+8\right|+10\ \textless \ 55|x+8|+10\ \textless \ 55
Subtract 10 from both sides.
9\left|x+8\right|+10-10\ \textless \ 55-10
9\left|x+8\right|\ \textless \ 45
Divide both sides by 9.
\frac{9\left|x+8\right|}{9}\ \textless \ \frac{45}{9}
\left|x+8\right|\ \textless \ 5
When we got absolute value, we are going to get two results.
x+8\ \textless \ 5
and
x+8\ \textgreater \ -5

Let's solve the first one,
x+8\ \textless \ 5x+8\ \textless \ 5
Subtract 8 from both sides.
x+8-8\ \textless \ 5-8
x\ \textless \ -3x\ \textless \ -3

Let's solve the second one.
x+8\ \textgreater \ -5
Subtract 8 from both sides.
x+8-8\ \textgreater \ -5-8
x\ \textgreater \ -13x\ \textgreater \ -13

Let's combine the ranges.
-13\ \textless \ x\ \textless \ -3

The attachment shows how would you graph it.
You can feel free to let me know if you have any questions regarding this.
Thanks!

- TetraFish

3 0
3 years ago
Describe two ways you can use the table to write a proportion
ale4655 [162]
You can use a table like this x  -1 0  1  2
                                              y   0  2  4  6
and a T table   
                         
4 0
3 years ago
Read 2 more answers
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