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jek_recluse [69]
3 years ago
15

Please answer this question now

Mathematics
2 answers:
maw [93]3 years ago
8 0

Answer:

70°

Step-by-step explanation:

64 * 2 = 128

Inscribed angle is half the arc, so arc BC is 128-90 = 38

A is half of arc BCD, which is 102 + 38 = 140

so m<A = 70°

borishaifa [10]3 years ago
7 0

Answer:

70 degrees

Step-by-step explanation:

Measure of arc ABC is 128 degrees, so measure of arc BC is 128-90 = 38 degrees.

Meausure of arc BCD is 102 + 38 = 140 degrees, so measure of angle A is 140/2 = 70 degrees

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8 0
3 years ago
Three tickets to attend an Off-Broadway show cost $81, 4 tickets cost $108, and 5 tickets cost $135. Show that the relationship
Mnenie [13.5K]

Answer:

  • k=27
  • y=27x

Step-by-step explanation:

3 tickets to attend an Off-Broadway show cost $81,

4 tickets cost $108; and

5 tickets cost $135.

Let the price of a ticket=k

Therefore:

  • 3k=81
  • 4k=108
  • 5k=135

Solving any of the equation above gives: x=27

We therefore have:

\left|\begin{array}{c|c|c|c|c|c}$Tickets&1&2&3&4&5\\$Total Cost(\$)&27&54&81&108&135\end{array}\right|

Let y be the total cost of x tickets

  • From the above, the constant of proportionality, k=27

An equation for the relationship is therefore:

y=27x (where x is the number of tickets and y is the total costs (in $)).

5 0
3 years ago
Question 2:
Ugo [173]

With the frequecy distribution shown in the 50 cities of pakistan,

  • range = 18
  • mean = 18.1
  • median = 19.8333
  • mode = 19.125
  • kurtosis = 2.7508
  • Standard deviation = 3.75

<h3>How to find the Range</h3>

= highest value - lowest value

= 26.5 - 8.5

= 18

<h3>How to find the mean</h3>

= ∑ f x / ∑ f

= ∑ f x / N

= 905 / 50

= 18.1

median

= lower limit + ( N/2 - C ) * h / ( frequency of the class interval )

C = cumulative frequency preceeding to the median class frequency

h = class interval

= 18.5 + ( 50 / 2 - ( 5 + 12 ) ) * 3 / 18

= 18.5 + 1.3333

= 19.8333

<h3>How to find the mode</h3>

The mode is the value with the highest frequency occurence. This is under class 18 - 20

mode = lower limit + ( ( f1 - f0 ) / (2*f1 - f0 - f2 ) ) * h

f1 = fequency of the modal class

f0 = freqency of the preceeding modal class

f2 = frequency of the next modal class

h = class interval

= 18.5 + ( ( 18 - 12 ) / (2 * 18 - 12 - 8 )  ) * 3

= 18 + ( 0.375 ) * 3

= 19.125

<h3>How to find the standard deviation </h3>

= sqrt ( 1 / N ∑ f ( x - x' )^2 )

= sqrt (1  / 50 * 706.5

= 3.7589

<h3>How to solve for relative dispersion </h3>

=  standard deviation / mean

= 3.7589 / 3

= 1.2530

<h3>What is the variance? </h3>

= ( standard deviation )^2

= ( 3.7589 )^2

= 14.1293

<h3>How to solve for kurtosis</h3>

=  ∑ f ( x - x' )^4 / ( N * ( standard deviation )^4 )

= 27459.405 / ( 50 * 3.7589^4 )

= 2.7509

Read more on frequency distribution here: brainly.com/question/1094036

4 0
2 years ago
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