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jek_recluse [69]
3 years ago
15

Please answer this question now

Mathematics
2 answers:
maw [93]3 years ago
8 0

Answer:

70°

Step-by-step explanation:

64 * 2 = 128

Inscribed angle is half the arc, so arc BC is 128-90 = 38

A is half of arc BCD, which is 102 + 38 = 140

so m<A = 70°

borishaifa [10]3 years ago
7 0

Answer:

70 degrees

Step-by-step explanation:

Measure of arc ABC is 128 degrees, so measure of arc BC is 128-90 = 38 degrees.

Meausure of arc BCD is 102 + 38 = 140 degrees, so measure of angle A is 140/2 = 70 degrees

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y^{\prime\prime}-y=0,~~~y(0)=2,~~y^\prime(0)=-\dfrac{1}{2}.

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y^\prime=me^{mx},~~~~~y^{\prime\prime}=m^2e^{mx}.

Substituting these values in the given differential equation, we have

m^2e^{mx}-e^{mx}=0\\\\\Rightarrow (m^2-1)e^{mx}=0\\\\\Rightarrow m^2-1=0~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mx}\neq0]\\\\\Rightarrow m^2=1\\\\\Rightarrow m=\pm1.

So, the general solution of the given equation is

y(x)=Ae^x+Be^{-x}, where A and B are constants.

This gives, after differentiating with respect to x that

y^\prime(x)=Ae^x-Be^{-x}.

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y(0)=2\\\\\Rightarrow A+B=2~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

and

y^\prime(0)=-\dfrac{1}{2}\\\\\\\Rightarrow A-B=-\dfrac{1}{2}~~~~~~~~~~~~~~~~~~~~~~~~(ii)

Adding equations (i) and (ii), we get

2A=2-\dfrac{1}{2}\\\\\\\Rightarrow 2A=\dfrac{3}{2}\\\\\\\Rightarrow A=\dfrac{3}{4}.

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Substituting the values of A and B in the general solution, we get

y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.

Thus, the required solution of the given IVP is

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