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alexdok [17]
3 years ago
7

Evaluate 5+x-5*8 for x = 7

Mathematics
1 answer:
Sladkaya [172]3 years ago
8 0

Answer:

- 28

Step-by-step explanation:

Plug in 7 for x

5 + 7 - 5 x 8

5 + 7 - 40

12 - 40

-28

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Suppose that 40 deer are introduced in a protected wilderness area. The population of the herd
Scorpion4ik [409]

The horizontal asymptote of the function is the minimum number of deer in the area.

  • The equation of horizontal asymptote is: \mathbf{y = 40}
  • The horizontal asymptote means that, the number of deer will never be less than 40

The equation is given as:

\mathbf{f(x) = \frac{40 + 2x}{1 + 0.05x}}

Expand the numerator

\mathbf{f(x) = \frac{40(1 + 0.05x)}{1 + 0.05x}}

Cancel out the common factor

\mathbf{f(x) = 40}

Hence, the equation of horizontal asymptote is:

\mathbf{y = 40}

The horizontal asymptote means that, the number of deer will never be less than 40

Read more about horizontal asymptotes at:

brainly.com/question/4084552

8 0
2 years ago
Write the polynomial in standard form 7x+3+5x^2
natka813 [3]
It’s should 5x^2+7x+3 in standard form
5 0
2 years ago
Cody's Gym charges a $15 fee to join and $30 per month. Tyler's Gym charges a $30 fee to join and $20 per month. Write an inequa
posledela

Answer:

<u>After (3/2) months Tyler's gym would be a better deal.</u>

Step-by-step explanation:

Let x the number of months

Cody's Gym charges a $15 fee to join and $30 per month

y₁= 15 + 30x (1)

Tyler's Gym charges a $30 fee to join and $20 per month

y₂ = 15 + 30x (2)

See the attached figure which represent the graph of y₁ (with blue color) and y₂ (with red color)

The point of intersection between y₁ and y₂ is ( 3/2 , 60)

After 3/2 months Tyler's Gym charges will be less than Cody's Gym charges

So, the inequality will be:

<u>After (3/2) months Tyler's gym would be a better deal.</u>

​

3 0
3 years ago
How many solutions does this linear system have y=2x-5. -8-4y=20​
ollegr [7]

Answer:

One solution

Step-by-step explanation:

y = 2x – 5. –8x – 4y = –20. one solution: (–2.5, 0)

4 0
3 years ago
500 tickets were sold for a game for a total of $862.50. If adult tickets sold for $2.00 and children's tickets sold for $1.50,
Alexxandr [17]
You can work these in your head if you consider the revenue generated by the least contributor (children's tickets) and the difference in revenue between that and the larger contributor ($2.00 -1.50 = 0.50).

If all were children's tickets, the revenue would be 500*$1.50 = $750.00. The actual revenue exceeded that amount by $862.50 -750.00 = 112.50. This difference in revenue is made up by the sale of $112.50/$0.50 = 225 adult tickets. Then the number of children's tickets is 500 -225 = 275.

225 adult tickets were sold
275 children's tickets were sold.

_____
If you need an equation, you can write an equation using a variable for the number of adult tickets sold (the largest contributor).
.. (500 -a)*1.50 +a*2.00 = 862.50
.. 0.50a = (862.50 -750.00) . . . . . does this look familiar, yet?
.. a = 112.50/0.50 = 225
6 0
3 years ago
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